saving a double to a file as 4 characters?

ok i have a script for an interpreted language that i use to change large numbers into only 4 bytes inside a file. this is the script:

PHP Code:

---

{
    var value, byte, stack, MASK, i, numBytes;
    
    MASK = 255;
    
    value    = argument0;
    stack    = argument1;
    numBytes = argument2;
    
    //Push the low-order byte on the stack, moving other bytes lower.
    for (i = 0; i < numBytes; i += 1)
    {
        byte = MASK & value;
    
        ds_stack_push(stack, byte);
    
        value = value >> 8;
    }
} 


---

the problem is the ds_stack, i don't know how i can mock that in c++. I know c++ you can make stacks, but i'm just wondering is there a way to get around it. i don't know how to use a c++ stack very well yet so... any help would be appreciated.

well, the sizeof(double) probably will not be 4 bytes -- sizeof(double) on 32-bit machine is 8, not 4.

You can use fwrite() (or whatever the C++ equivalent is) to write a variable to a binary file.

[edit]
And what's var? Is it a typedef or something?
[/edit]

the script was for a different language. var specifies a variable that will go out of scope when the function ends.

ancient dragon, i don't see what you are saying. i don't think sizeof() does what i want.

He's just saying that you can't store an 8 byte variable in 4 bytes without losing some of its precision. A float would fit into 4 bytes.

errr. ok i'm dumb. i meant float not double. thank you for your help.