calling exit() crashes

In my program I have this function:

Code:

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void menuTestExit(Node* root) {
        printf("before delete\n");
        delete root;
        printf("after delete\n");
        exit(0);
}

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I have to do it this way because I'm using glut. The problem is that this code always prints before delete and after delete, then creates a JIT debugging error (even when I run the executable directly). Is this something I should even be worried about, and if so, how do I fix it?

Are you checking that root points somewhere before deleting it?

Don't use exit in C++

Quote:

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Originally Posted by sand_man

Are you checking that root points somewhere before deleting it?

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Yes. It's a valid pointer. I also tried just commenting out the delete line, but it still gives the same error.

Quote:

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Originally Posted by anonytmouse

Don't use exit in C++

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The issue, if I'm understanding correctly, is that destructors don't get called implicitly when exit is called because the stack doesn't unroll, right? This is why I delete the root and kill all the data. I tried rewriting the exit function like this:

Code:

---

void menuTestExit(Node* root) {
        printf("before delete\n");
        delete root;
        printf("after delete\n");
//        exit(0);
        throw(ExitExc());
}

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where ExitExc is just an empty class like this:

Code:

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class ExitExc {};

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Then I changed the top like this:

Code:

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int main() {
//some other stuff
        try {
                glutMainLoop();
        } catch (ExitExc e) {
        }
        return 0;
}

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But this gives the same error.

The problem is elsewhere in your code. Check your memory allocation/deallocation, buffer overruns, destructors, etc.