invoking conversion via .operator

Code:

---

class MyClass {
public:
  template <typename T> operator T& () { /* code here */ }
}

int my_func()
{
  MyClass mc;

  mc.operator int& (); // !! fails to compile: error: no matching function for call to ‘MyClass::operator T&()’
}

---

i need to invoke the conversion that way: object.operator int&
(the reason is that im using bison, and trying to hack that damn stack/union stuff...)
(int&)object works though - but i can't use that.

it seems that the template argument needs to be specified in order to explicitely instanciate a function template. how can that be done?

Code:

---

template<class T>
class MyClass {
public:
  operator & () { /* code here */ } //+,-,[],* and many more are valid operators
}

int my_func()
{
  MyClass mc;

  mc.operator int& (); // !! fails to compile: error: no matching function for call to ‘MyClass::operator T&()’
}

---

Im not sure if you can specifiy operators with templates

me neither ^^

but i still have slight hope that it is possible :)


edit: um... i mean the code works if i use the usual c-style cast syntax:
(double&)object, (float&)object, etc... so operators and templates actually work.
im not sure wheter that "alternative" syntax (something like object.operator type ()) works :(

Is this what you are talking about?

Code:

---

template<class T>
class myClass
{
    public:
        T operator &()
        {
            return data;
        }
    private:
        T data;
};


int main()
{
    myClass<int> mc;
    mc.operator &();
}

---

Or...

Code:

---


class myClass
{
    public:
        template<class T>
        T operator &()
        {
            return data;
        }
    private:
        int data;
};


int main()
{
    myClass mc;
    mc.operator &<int>();
}

---

lol, simply overloading the reference operator, ya, thats what i was looking for.
thxalot!

That's the addressof operator, not reference operator. (The reference "operator" is not overloadable.)