bit o' fun

Code:

---

#include <stdio.h>
 
int main(void) {
  int i = 5;
  /* Add a line of code here to make the printf() below output 5 */
  i = 8;
  printf("%d\n", i);
  return 0;
}

---

Umm:

Code:

---

#include <stdio.h>
 
int main(void) {
  int i = 5;
  #define printf printf("5\n"); 
  i = 8;
  printf("%d\n", i);
  return 0;
}

---

anyone come up with anything different..?? :cool:

Same idea:

Code:

---

#include <stdio.h>

int main(void)
{
        int i = 5;
        #define jab \
        i = 8;
        printf("%d\n", i);

        return(0);
}

---

or with two lines (under the assumption your x86)

Code:

---

#include <stdio.h>

int main(void)
{
        int i = 5;
        __asm add ebp,4
        i = 8;
        __asm sub ebp,4
        printf("%d\n", i);

        return(0);
}

---

used more than one line..!!! :P

Code:

---

#include <stdio.h>

int main(void)
{
        int i = 5;

        if (i == 0)
                i = 8;

        printf("%d\n", i);
        return 0;
}

---

I know its kind of cheesey...

Code:

---

#include <stdio.h>
 

int main(void) {
  int i = 5;
  while(false)
  i = 8;
  printf("%d\n", i);
  return 0;
}

---

Some more x86 asm.

Code:

---

#include <stdio.h>
 
int main(void) {
  int i = 5;
a: __asm jmp a+12
  i = 8;
  printf("%d\n", i);
  return 0;
}

---

Bah...why not?

Code:

---

#include <stdio.h>
 
int main(void)
{
  int i = 5;
  return printf("5"),0;
  i = 8;
  printf("%d\n", i);
  return 0;
}

---

Code:

---

#include <stdio.h>
 
int main(void) {
  int i = 5;
  /* Add a line of code here to make the printf() below output 5 meow!
  i = 8; */
  printf("%d\n", i);
  return 0;
}

---

Quote:

---

Originally Posted by Quantum1024

Some more x86 asm.

Code:

---

#include <stdio.h>
 
int main(void) {
  int i = 5;
a: __asm jmp a+12
  i = 8;
  printf("%d\n", i);
  return 0;
}

---

---

Does that mean "i = 8;" is 12 bytes long in the .exe?

no,

Code:

---

a: __asm jmp a+12
i = 8;

---

is assumed to be 12 bytes long i = 8; AND the jmp