show matrix

Code:

---

#include <stdio.h>
#include <stdlib.h>
int show_matrix(int column, int row, int matrix[column][row]);

int main(void)
{
int m = 2;

int matrix[m][m] = { {1,2}, {1,2} };

show_matrix(m,m,matrix);
return 0;
}

int show_matrix(int column,int row,int matrix[column][row])
{
        int m,n;
        for( m = 0; m < column; m++ )
        {
                printf("\n");
                for(n = 0; n < row; n++)
                {
                        printf("%3d",matrix[m][n]);
                }
        }

---

when i compile this,it can run,but it gives me a lot of warning,can someone give me any solution?

How about fixing your warnings? Oh, and unless you're compiling this as C99, you can't have your array done that way, which is probably what it's complaining about.


Quzah.

so,without c99,is it possible to use 2d variable array?

No. Simulate it with dynamic memory allocation. A quick forum search on the topic should yield lots of code for you to play with.


Quzah.

thanks quzah,i really appreciate ur help...:)

I hav made some modifications:

Code:

---

#include <stdio.h>
#include <stdlib.h>
#define m 2
int show_matrix(int,int,int matrix[m][m]);

int main(void)
{
int matrix[m][m] = { {1,2}, {1,2} };

show_matrix(m,m,matrix);
return 0;
}

int show_matrix(int row,int coloum,int matrix[m][m])
{
        int c,r;
        for(r=0;r<row;r++)
        {
                printf("\n");
                for(c = 0; c < coloum; c++)
                {
                        printf("%3d",matrix[r][c]);
                }
        }
        return 0;
}

---

In the function declaration u only need to specify the data type except for a matrix.
It is a good practice to declare m as a constant using #define.
and ur row-coloum convension is wrong. The outer loop should vary row and inner loop must vary coloum.

Finally try to code it more simple.