how do you repeat cout statements?

ok my question is if a person in used my code and pressed 0 to not roll how do you repeat it again until the user enters 1 for yes?

Code:

---

//adds the iostream library to the program
#include <iostream>
//adds the iomanip library to the program
#include <iomanip>
//adds the math library to the program
#include <cmath>
// this one is for the system library =)
#include <cstdlib>

 
//informs the compiler you are using the standard library set
using namespace std;

int num1,num2;
int yes;
int main ()
{

  cout << "Chapter Program 5\n";
  cout << "Round 1\n";
  cout << "Would you like to roll this round? [1 for yes, 0 for no]:";
  cin  >> yes;
if (yes < 1)
  cout << "Would you like to roll this round? [1 for yes, 0 for no]:";
 
else
cout << "You have rolled a" << num1 << "and a" <<num2 << endl;

{

}
    system("pause\n\n\n\n");
return 0;
}

---

Code:

---

#include <iostream>
using namespace std;

int main ()
{
  for ( ;; )
  {
      int yes;
      cout << "Would you like to roll this round? [1 for yes, 0 for no]:";
      if ( cin >> yes && yes == 1 )
      {
        cout << "M'Kay!\n";
      }
      else
      {
        break;
      }
  }
  return 0;
}

---

Code:

---

#include<iostream>
using namespace std;

int main()
{
        int num = 0;
       
        do
        {
                cout<<"Enter a number: ";
                cin>>num;
       
        }while(num != 20);


        num = 30;
        while(num < 50)
        {
                cout<<"Enter another number: ";
                cin>>num;
        }

        return 0;
}

---

i get a problem that when you enter 0 you get 2 lines saying the same thing. how do i get rid of one of the lines?

Code:

---


//adds the iostream library to the program
#include <iostream>
//adds the iomanip library to the program
#include <iomanip>
//adds the math library to the program
#include <cmath>
// this one is for the system library =)
#include <cstdlib>

 
//informs the compiler you are using the standard library set
using namespace std;

int num1,num2;
int Choice;
int main ()
{
  for ( ;; )
  {
      int yes;
      cout << "Would you like to roll this round? [1 for yes, 0 for no]:\n\n";
      if ( cin >> yes && yes == 0 )
      {
        cout << "Would you like to roll this round? [1 for yes, 0 for no]:\n\n";
        cout << "\n\n\n";
      }
      else
      {
        cout << "you rolled\n\n\n";
        break;
      }
  }
      system("pause\n\n\n");
  return 0;
}

---

anyone got any answers to this annoying problem?

i would do

so you need it to look like this (below)

Code:

---

std::string yes;
cin >> yes;
if(yes == "yes"){do whatever you think of;}

---

where do you put that? in int main?

any ideas?

Code:

---

using namespace std;

int num1,num2;
int Choice;
int main ()
{
  for ( ;; )
  {
      int yes;
      cout << "Would you like to roll this round? [1 for yes, 0 for no]:\n\n";
      if ( cin >> yes && yes == 0 )
      {
        //cout << "Would you like to roll this round? [1 for yes, 0 for no]:\n\n";
        //cout << "\n\n\n";
      }
      else
      {
        cout << "you rolled\n\n\n";
        break;
      }
  }
      system("pause\n\n\n");
  return 0;
}

---

is this what you want ?
Kurt

yes that is part of what i wanted to do but i need tomake it so that
if a person enters anything else ( like A,0,2,3,5,35)but a 1
then

Code:

---

//cout << "Would you like to roll this round? [1 for yes, 0 for no]:\n\n";

---

For your previous problem of the prompt appearing twice when they answer 0, you need to remove (or comment out as Enahs did) the extra prompt inside the if. This isn't necessary because if they answer 0, the loop wil continue again and the original prompt will be displayed.

If you want to worry about bad input (something other than 0 or 1), then it is a little more complicated. A common way to handle bad input is this:

Code:

---

while (!(cin >> yes) || (yes != 0 && yes != 1))
{
  // clear any fail state from the user entering characters instead of a number
  cin.clear();

  // remove all bad characters from the input stream to start fresh
  cin.ignore(numeric_limits<streamsize>::max(), '\n');

  // Prompt again here...
}

// Use yes as you would normally.

---

Note that you have to #include <limits> to use numeric_limits. You can also just use a large number there to make sure all bad characters are ignored.

That code will keep prompting until 0 or 1 is input. Then you can handle 0 or 1 as you wish.