Frustrating Error

Hey! Thanks in advance for trying to help! Anyways, I have a ";" error that keeps flashing up.

Wrestling.cpp(46) : error C2146: syntax error : missing ';' before identifier 'cout'

And I swear I have a semicolon before the line. So I'm hoping you guys can help this newbie out.

Here is the code:

(I've underlined the line that needs a semicolon before it)

Code:

---

#include <iostream>
#include <string>

using namespace std;

struct person
{
        double name;
        int weight;
};

void getwrestlerdata(struct person &);
void printwrestlerdata(struct person);
int main()
{
        person wrestler;
        getwrestlerdata(wrestler);
        printwrestlerdata(wrestler);

        return 0;
}


void getwrestlerdata(struct person &s)
{
        cout<<"Please enter student's name\n";
        cin>>s.name;

        cout<<"Please enter student's weight(in pounds)\n";
        cin>>s.weight;

return;
}

void printwrestlerdata(struct person s)
{
        cout<<s.name<<", who weighs "<<s.weight<<", is classified as a ";

        if(s.weight<100)
                cout<<"lightweight. "<<endl;

        else if(s.weight>99 && s.weight<200)
                cout<<"middleweight. ";

        else(s.weight>200)
                cout<<"heavyweight."<<endl;
   
        return;
}

---

Its really frustrating me...

I just don't understand what I'm doing wrong.

here's is the corrected code...see the changes in bold

Code:

---

#include <iostream>
#include <string>

using namespace std;

struct person
{
        char name[20];
        double weight;
};

void getwrestlerdata(struct person &);
void printwrestlerdata(struct person);
int main()
{
        person wrestler;
        getwrestlerdata(wrestler);
        printwrestlerdata(wrestler);

        return 0;
}


void getwrestlerdata(struct person &s)
{
        cout<<"Please enter student's name\n";
        cin>>s.name;

        cout<<"Please enter student's weight(in pounds)\n";
        cin>>s.weight;

return;
}

void printwrestlerdata(struct person s)
{
        cout<<s.name<<", who weighs "<<s.weight<<", is classified as a ";

        if(s.weight<100)
                cout<<"lightweight. "<<endl;

        else if(s.weight>99 && s.weight<200)
                cout<<"middleweight. ";

        else if(s.weight>200)
                cout<<"heavyweight."<<endl;
   
        return;
}

---

Or better still:

Code:

---

struct person
{
        string name;
        double weight;
};

---

char name[20]; defines a character array with space for twenty individual characters; if you enter a name which has more than twenty characters (unlikely in this case admittedly), the characters beyond the twentieth will not be stored in the array. A string is able to expand to however many characters are entered, and thus does not suffer this problem.