converting double to long int

I'm trying to convert a double to a long int, but i keep getting a warning message saying :

34 C:\Dev-Cpp\PROG1B.cpp [Warning] converting to `long int' from `double'

How do i ignore the warning so i can compile it?

Here's how i started setting up the code:

Code:

---


#include <iostream>
#include <math.h>
#include <cmath>

using namespace std;

int main()
{

//Declaring Variables

double tendered;
double purchase;
double chg;
long change;
int fives;
int ones;
int half;
int quarters;
int dimes;
int nickels;
int pennies;
   
    cout << "Enter purchase amount: ";
    cin >> purchase;
   
    cout << "Enter tendered amount: ";
    cin >> tendered;
   
    //Calculating change amount
    chg = tendered - purchase;
   
    //Converting double to long
    change = ceil(chg * 100);
   
   
    //Display error message if change is more than 19.99
   
    If (chg > 19.99)
      cout << "Amount to return is: " << chg << "--Sorry just dont have that amount of change";
    getch();
    return 0;
   
    fives = change / 5;
    ones = (change - 5) / 1;
   
    cout << "Fives" << fives;

return 0;
}

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typecast it.....long(expression);

Quote:

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Originally Posted by gunshipolitico

How do i ignore the warning so i can compile it?

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How do you ignore a warning? You ignore it by... ignoring it. A warning does not hinder the compilation of code to object code, it's the errors you gotta watch out for. For the most part however you should pay attention to the warnings your compiler spits out and do your best to understand them and the effect they may have on the program.

Code:

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#include <math.h>
#include <cmath>

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You only need one of those, lose the first, keep the second.

ok. I have an error that I think is the main problem:

38 C:\Dev-Cpp\PROG1B.cpp `If' undeclared (first use this function)
(Each undeclared identifier is reported only once for each function it appears in.)

I thought that i did the if statement correctly, but apparently not.

Code:

---


#include <iostream>
#include <cmath>

using namespace std;

int main()
{

//Declaring Variables

double tendered;
double purchase;
double chg;
long change;
int fives;
int ones;
int half;
int quarters;
int dimes;
int nickels;
int pennies;
   
    cout << "Enter purchase amount: ";
    cin >> purchase;
   
    cout << "Enter tendered amount: ";
    cin >> tendered;
   
    //Calculating change amount
    chg = tendered - purchase;
   
    //Converting double to long
    change = ceil(chg * 100);
   
   
    //Display error message if change is more than 19.99
   
    If (change > 1999.00)
      cout << "Amount to return is: " ;
      cout << chg << " --Sorry, I dont have that amount of change" << endl;

    //change = ceil(chg*100);           
   
    fives = change / 500;
       
    cout << "Fives" << fives;

return 0;
}

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Remember C++ is a case-sensitive language. If and if are two completely different things.

Quote:

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Originally Posted by hk_mp5kpdw

Remember C++ is a case-sensitive language. If and if are two completely different things.

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oops....well the fixed everything. Thanks!