Newbie in problem with looping

hii all,

i am a total newbie here and also a BRAND NEW learner of C

as a part of my first assignment in class i have done the following
coding. but having problem wth this. is there any one who wishes
to help me??

Code:

---


#include <stdio.h>                       

void main()

{

char line;         

clrscr();

printf("Choose your initial state:");

line=getchar();

    switch(line)    {
                case '1':
                printf("Step 1:\t L==Red\t\t\t\tGreen\n");

                case '2':
                printf("Step 2:\t L==Red\t\t\t\tAmber\n");

                case '3':
                printf("Step 3:\t L==Red+Amber\t\t\tRed\n");

                case '4':
                printf("Step 4:\t L==Green\t\t\tRed\n");

                case '5':
                printf("Step 5:\t L==Amber\t\t\tRed\n");

                case '6':
                printf("Step 6:\t L==Red\t\t\t\tRed+Amber\n");
                }
        getch();
}

---

My problems are:
1. I want to use looping , but unfortunately both while and for loops are failed.
2. I want to run the loops depending on user demand.



Is there any 1 to help this newbie???

JUST TELL ME IF I NEED TO PRACTICE OR ADD ANY SPECIFIC FUNCTION

IF Any 1 can suggest any good pdf to learn switch & loops with example, I will be grateful

I don't particularly see why you would want loops in there. That is, unless you want to cycle through the steps. What specifically is it that you're trying to do ?

And as for ressources on learning about loops and switch statements :

For loops :
http://www.cprogramming.com/tutorial/c/lesson3.html

For switch statements :
http://www.cprogramming.com/tutorial/c/lesson5.html

And main() should return int.

would any1 plz find an error that is causing LOOP-error

Code:

---



#include <stdio.h>
#include <conio.h>
void main()
{

char line;

for(line=0;line<7;line++){
  printf("Choose your initial state:");
  line=getchar();

  switch(line)
                {
                case '1':
                printf("Step 1:\t L==Red\t\t\t\tGreen\n");
                printf("Step 2:\t L==Red\t\t\t\tAmber\n");
                printf("Step 3:\t L==Red+Amber\t\t\tRed\n");
                printf("Step 4:\t L==Green\t\t\tRed\n");
                printf("Step 5:\t L==Amber\t\t\tRed\n");
                printf("Step 6:\t L==Red\t\t\t\tRed+Amber\n");
                printf("Choose your initial state:");
                scanf("%d",&line);
                break;

                case '2':
                printf("Step 2:\t L==Red\t\t\t\tAmber\n");
                printf("Step 3:\t L==Red+Amber\t\t\tRed\n");
                printf("Step 4:\t L==Green\t\t\tRed\n");
                printf("Step 5:\t L==Amber\t\t\tRed\n");
                printf("Step 6:\t L==Red\t\t\t\tRed+Amber\n");
                printf("Step 1:\t L==Red\t\t\t\tGreen\n");
                printf("Choose your initial state:");
                scanf("%d",&line);
                break;

                case '3':
                printf("Step 3:\t L==Red+Amber\t\t\tRed\n");
                printf("Step 4:\t L==Green\t\t\tRed\n");
                printf("Step 5:\t L==Amber\t\t\tRed\n");
                printf("Step 6:\t L==Red\t\t\t\tRed+Amber\n");
                printf("Step 1:\t L==Red\t\t\t\tGreen\n");
                printf("Step 2:\t L==Red\t\t\t\tAmber\n");
                break;

                case '4':
                printf("Step 4:\t L==Green\t\t\tRed\n");
                printf("Step 5:\t L==Amber\t\t\tRed\n");
                printf("Step 6:\t L==Red\t\t\t\tRed+Amber\n");
                printf("Step 1:\t L==Red\t\t\t\tGreen\n");
                printf("Step 2:\t L==Red\t\t\t\tAmber\n");
                printf("Step 3:\t L==Red+Amber\t\t\tRed\n");
                break;

                case '5':
                printf("Step 5:\t L==Amber\t\t\tRed\n");
                printf("Step 6:\t L==Red\t\t\t\tRed+Amber\n");
                printf("Step 1:\t L==Red\t\t\t\tGreen\n");
                printf("Step 2:\t L==Red\t\t\t\tAmber\n");
                printf("Step 3:\t L==Red+Amber\t\t\tRed\n");
                printf("Step 4:\t L==Green\t\t\tRed\n");
                break;

                case '6':
                printf("Step 6:\t L==Red\t\t\t\tRed+Amber\n");
                printf("Step 1:\t L==Red\t\t\t\tGreen\n");
                printf("Step 2:\t L==Red\t\t\t\tAmber\n");
                printf("Step 3:\t L==Red+Amber\t\t\tRed\n");
                printf("Step 4:\t L==Green\t\t\tRed\n");
                printf("Step 5:\t L==Amber\t
\t\tRed\n");
       
                default:
                printf("Choose your initial state:");
                  line=getchar();
                break;           

                }
                continue;
                }
               


}

---

The statement

Code:

---

line = getchar();

---

inside the for-loop overwrites the value of line in the for-loop. Use different variables.
Kurt

And main() should return int! :)

Change this

Code:

---

void main() {
    /* ... */
}

---

to

Code:

---

int main() {
    /* ... */
    return 0;
}

---

Your default case doesn't do what you think it does. And you don't need continue at the end of the for loop. Nor <conio.h>.

Your case '6' does'nt contain a break statement but that will not give you a loop error.
Take another int variable for for loop.as already told.