sum of 2 int arrays

if i have 2 int arays what is the best way to sum the two in new array?

A for loop, and use of the + operator

Code:

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#include "stdafx.h"
#include <iostream>
using namespace std;

void print (int* a, int* b, int arraySize) {
  int* aPtr;
  int* bPtr;
  int i;

  cout << "The values:" << endl;
  for (i = 0, aPtr = a, bPtr = b; i < arraySize;
      cout << "A[" << i << "]: " << *(aPtr++) << endl,
      cout << "B[" << i << "]: " << *(bPtr++) << endl, i++);
}

int main() {
  const int arraySize = 10;
  int* a = new int[arraySize];
  int* b = new int[arraySize];
  int* aPtr;
  int* bPtr;
  int i;

  // initialise
  for (i = 0, aPtr = a, bPtr = b; i < arraySize; *(aPtr++) = 1, *(bPtr++) = 2, i++);

  // print
  print(a, b, arraySize);

  // copy
  for (i = 0, aPtr = a, bPtr = b; i < arraySize; *(aPtr++) = *(bPtr++), i++);

  // print
  print(a, b, arraySize);
}

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Maybe:

Code:

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transform(start of array1, end of array1, start of array 2, start of sum array, plus<int>());

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Assumes array 2 and the sum array are at least as big as array 1. Need to #include the <algorithm> and <functional> headers for that to work. Still a couple details for you to work out on your own there.

Edit: Probably not the best way... but I like it.

thanks i will try them

Code:

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for (i = 0, aPtr = a, bPtr = b; i < arraySize; *(aPtr++) = 1, *(bPtr++) = 2, i++);

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You shouldn't cram too much into a for loop (or while loop) header. It can get hard to read.

BTW, instead of *(aPtr++) you can use *aPtr++.

Quote:

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Originally Posted by dwks

You shouldn't cram too much into a for loop (or while loop) header. It can get hard to read..

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Amen to that! :D It also makes debugging a nightmare, and you will hate yourself for doing that in a very short time when you have forgotton what that is supposed to do. :eek: and that semicolon at the end of the line will cause many hours of grief if you ever decide to add code that should be executed on every iteration of the loop, and you don't know why it doesn't work. :rolleyes: