Just trying to cout an empty set

Can someone explain to me how to cout an empty set from this code? I know that the second idx should reference the array but don't know how to do it.

main.cpp

Code:

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int main()
{
        IntegerSet a;

        cout << "Empty Set" << endl;
        a.printSet();
        getch();
}

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IntegerSet.cpp

Code:

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void IntegerSet::printSet()
{
        for( int idx = 1; idx <= arraySize; ++idx )
                cout << idx << ")" << setw( 3 ) << idx << endl;
}

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IntegerSet.h

Code:

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#ifndef INTEGERSET_H
#define INTEGERSET_H

const int arraySize = 100;

class IntegerSet
{
public:
void printSet();

private:
        int array;

};

#endif

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I do not see an array anywhere in the code you posted?
But if you did have an array, you would 'cout << array_name[idx]' in your for loop (is one method).

Quote:

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Originally Posted by Enahs

I do not see an array anywhere in the code you posted?
But if you did have an array, you would 'cout << array_name[idx]' in your for loop (is one method).

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and make sure it's zero counted i.e. change your code

Code:

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for( int idx = 1; idx <= arraySize; ++idx )

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to

Code:

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for( int idx = 0; idx < arraySize; ++idx )

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