time class

Greetings,

I am trying to modify the definition of this "Time" object so that time is represented internally as the number of seconds before or after noon. I want time before noon to be a negative number, time after noon will be positive and noon will be 0.
Not for sure what to look at first. Ok the int hour is time 0 to 23, minute and sec o to 59. How do I define noon as 0, then go negative? The time as of now is initialized to 12am as 0. So how do I initialize the time so that 12pm is 0? Then to go in the neg direction? 12 am to 11:59am is negative and 12:01pm to 11:59 pm is positive.

Thank you
Terri


#ifndef TIME6_H
#define TIME6_H

class Time {
public:
Time( int = 0, int = 0, int = 0 );

// set functions
Time &setTime( int, int, int );
Time &setHour( int );
Time &setMinute( int );
Time &setSecond( int );


int getHour() const;
int getMinute() const;
int getSecond() const;


void printMilitary() const;
void printStandard() const;
private:
int hour;
int minute;
int second;
};

#endif

Forgot to mention that I only need 1 data member. See If I could use 2 I would use something like this maybe:

private;
int sinceMidnight; // seconds since midnight
int aftermidnight; // seconds after midnight
};