Printing part of a local variable

Hello,

I was wondering if there is a way to only get a certain part of text from a variable. For example if y = hello hey sup howdy, is there any easy way to choose and print one of those varialbes? Thanks!

i dint get u. can u elaborate on it.

ok,

I have a varialbe that is the following:

y = -1 hello hey sup -2 bye cya

Is there a way that I can get it to print everything except everything after -2?

Sure, you can use strstr() to find the bits of strings which interest you.

Code:

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char test[] = "this is a message";
char *p = strstr( test, "mess" );
if ( p != NULL ) {
  len = p - test;
  printf( "%.*s\n", len, test );
}

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Thats almost what I need, Salem. But how would I want to include everything [I]after[I] "message"?

printf("%s",p) ?

Probably more like

Code:

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printf("%s", p+strlen("message "));

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Quote:

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Originally Posted by dwks

Probably more like

Code:

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printf("%s", p+strlen("message "));

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may be this,just a matter of space :p .
printf("%s", p+strlen("message"));

No, since your way would print a space in front of p. :)

c compiler ignores white spaces like , p.but strlen will give 1 more character for space in string.so i think ur will eat a character after message

Quote:

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c compiler ignores white spaces . . .

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It does, but not in strings. Check a binary dump if you like (or use gcc -S).

Quote:

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strlen will give 1 more character for space in string.so i think ur will eat a character after message

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Not if the message is

Code:

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"this is the message and a long one at that"

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Then your code would produce a pointer to a string that looks like this:

Code:

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" and a long one at that"

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Wheras mine would point to

Code:

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"and a long one at that"

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Do you see? :)