char to binary conversion

hello, I have a question about how to convert a single character to its binary equivalent. I have find the way to do it for integer numbers:

Code:

---

int c=8;
while(c>0) {cout<<c%2;c=c/2;}

---

to show the 'reversed' binary. also I have find the way to do it with plain characters, only get its ascii and do the same as before, so:

Code:

---

int bin[8];
int pe;
char c='a';
printf("dec:%d\n",c);
pe=7;
while(c>0)
    {
    bin[pe]=c%2;
    c=c/2;
    pe--;
    }
for(int np=pe;np>=0;np--) {bin[np]=0;}
printf("bin:");
for(int q=0;q<8;q++) {printf("%d",bin[q]);}
printf("\n");

---

but how can I convert an accentuated character to its binary representation? the method of convert its ascii number does not work here. also seems not to work here the loop though a

while(c<0)

mutiplying instead '%'.
How can I do it?
Thank's in advance
Niara

A bitset is very easy to use:

Code:

---

#include <bitset>
#include <iostream>

...

char c = 'A';

// Convert character into bitset
std::bitset<8> bits(static_cast<unsigned long>(c));

// Display bitset
std::cout << bits << std::endl;

---

On my machine this outputs: 01000001

http://cboard.cprogramming.com/searc...earchid=218529

You'll note that this is quite a frequent subject with many solutions. Filter through the binary search tree and binary file writing results and that search will have many helpful replies with example source you might like.

hello both, thank's for your time and help.
hk_mp5kpdw: that function gives exactly what I was trying to do, so I will try to find a bit more info about related functions and functionality.
Tonto: yes, I never used the searcher; so I'll be to take into account before ask new problems, I know that a previous search can help me on orientating my doubts to some exact interest points.
Niara