HW Question

Write a function that initializes all elements of
a character array to blanks. The function should take
two arguments. The first is a pointer to a character
array. The second is the number of elements in the
array. DO NOT USE BRACES '[' or ']' IN YOUR SOLUTION.

This is what I have does it look right?:
void blank (void)

{
char buff[50];
char *ptr;
ptr = buff;

*ptr = '\0';

puts (buff);


}

Thanks mattz

void blank(void)....

the problem states the function should take 2 arguments, so your function should be of the general form

return_type function_name(arg1_type arg1, arg2_type arg2)

Also, the question says do not use braces.... so buff[50] I'm guessing won't be acceptable...

Hope that helps.

Hi,
homework question ... again? ;°)=)
I'd advice you to check your books, it's a simple task, really.

Just think a little bit about!
- What's the difference between * and & ?
- What kind of function do you need?
- What should that function return?
- How can you pass arguments to a function?
- Which one of the arguments should be a const?
etc.

Have fun, and ask, if you run in *real* problems!

Here is what I HAVE..I did READ btw.

#include <stdio.h>




int blanks ( char* a, int num );


int main (void)

{ int x;
char buff[20];
char *buff_ptr;
buff_ptr = buff;

for (x=0; x < 5; x++)

blanks (buff_ptr, x);
return 0;

}


int blanks ( char *a, int num)
{

int i;

for (i = 0 ; i < num ; i++)
a[i] = '\0';


for (i = 0 ; i < num ; i++)
printf("%s\n",a[i]);

return 0;




}

Not sure if its valid...seems to have issues.

'\0' is normall seen as the end of a string... if you set every value to that in your string I'm guessing when you try to show it you will have an "empty" string. I would make it a space (' ') instead, and then probably add a '\0' onto the end.

You can avoid braces (a[i]) by using a pointer to move across the passed array...

char *ptr;

//set ptr to "point" at the first character in the string
//move across the string using the ptr
//set the value pointed to by that address to ' '

(for ptr = a, i = 0; i < num; i++, ptr++)
*ptr = ' ';


... or something like that... it's been a while...

Finally, I think it might be a good idea to initialize buff[20] in main to something to help you debug...

Thanks to all,
For those interested here is the answer:
#include <stdio.h>




int blanks ( char* a, int num );


int main (void)

{ int y;
int x =5;
char buff[5];
char *buff_ptr;
buff_ptr = buff;

//(x=0; x < 5; x++)

blanks (buff_ptr, x);

for (y=0; y < 5; y++)

printf("%c\n", buff[y]);

return 0;

}


int blanks ( char *a, int num)
{

int i;

for (i = 0 ; i < num ; i++)
*(a+i)= ' ';

return 0;




}
Mattz

Here's a better way:

memset( myBuf, ' ', sizeof( myBuf ) );

Quzah.

Wow...you are good :)

Thanks for help.