Squareroot help

Hey i'm trying to do a program that returns the answer to a squareroot!!! Please help...the answer I keep on getting is "1". Frustrating frustrating.

Code:

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#include <iostream>
using namespace std;

float Squareroot(float x);

int main() {
    float numberA;
    float squrtquotient;
   
    cout << "Hey maya here's your squareroot!" << endl;
    cout << "Enter your number to squareroot and you'll be off into happyland!\n\t" ;
    cin >> numberA;
    squrtquotient = Squareroot(numberA);
    cout << "\t" << squrtquotient << endl;
    cout << "\t\tWOWSERS!!!!!!!!!!!!!!" << endl;
    cin.get();
    return 0;
   
}

float Squareroot(float x) {
      cin.get();
      return (x/x) ;
      }

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Code:

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return (x/x);

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If you want to roll your own square root method, do a search on Newton-Raphson root-finding.

If you just want to get the square root, include the header <cmath>, and call the std::sqrt function.

x/x will always return 1, unless x is zero (in which case, the behaviour is implementation defined).

Why not use the std::sqrt() function, which is declared in the <cmath>? The only difference is that it accepts a double argument and returns a double ......

Quote:

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Originally Posted by MrWizard

Code:

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return (x/x);

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Hehe. Short, sweet, and to the point.

If you have no reason not to use cmath's sqrt(), use it. Otherwise, I'd recommend Newton's iteration. It's a beautiful thing. Like magic.

What is Newton's iteration?

when someone give you a specific name, this would
be a good time to go to

www.google.com and type that name into search feild,
possibly adding the word "c++" in there somewhere
to possibly narrow the field down.