problem working with char array

Hi all, i got a bit of a problem...

Code:

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char name[30];
char man[30];
.
.
.
//some value assigned to name
.
.
.
sprintf(man, "%s", &name);//where name is of the format ABECD.aid

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If i had the above code, and later in the code wanted to asign to man the same value without the extension. how would i go about doing that.

i do not know the lengh of name, and the name is different each time. so is the extension.


all help is greatly appreciated.

hi,

Rigth now i can think of 3 methods of doing it...

1. Write a function, where in you send the pointer of name and man and do a char by char copy till you get the "."

2. Using strtok() with "." as the second parameter..

3. strcpy name and man.. and then char by char check if its "." and when you find it replace it with '\0'

there could be other ways too.. but i can think of this three rite now.. !!!

Happy coding..

Quote:

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Originally Posted by bradleym83

Code:

---

char name[30];
char man[30];
.
.
.
//some value assigned to name
.
.
.
sprintf(man, "%s", &name);//where name is of the format ABECD.aid

---

---

lose the &name, it's sprintf(man, "%s", name);

If you're 100% positive that a '.' will exist then you can do:

Code:

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*strchr(man, '.') = '\0';

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If you're not, you can do

Code:

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char *p = strchr(man, '.');
if(p) *p = 0;

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