scanf and printf precedence

Hey,
does anyone knows why scanf always comes before any printf? how do I print any thing before an input?

PHP Code:

---

int a, b;
  printf("Enter 2 numbers:");
  scanf("%d %d", &a, &b);
  printf("%d %d", a, b); 


---

and it comes out:
12 47
Enter 2 numbers:12 47

Flush the output stream before calling scanf.

Code:

---

int a, b;
printf("Enter 2 numbers:");
fflush( stdout );
scanf("%d %d", &a, &b);
printf("%d %d", a, b);

---

If you print with a newline at the end, it will flush the output. Without, it may or may not. It doesn't have to. So it's really dependant on your OS / compiler / whatever it feels like.

Code:

---

printf("foo\n"); /* flushes output... */
printf("bar" ); /* doesn't */

---

fflush is only designed for output streams. You can't flush input with it. Or rather, it's undefined behaviour if you try it.


Quzah.

works like a charm. thank you