Printable View
hi
i have a problem
i need to do this
for example
i will write
welcome.to programming.welcome
then it will show me this
we use "w" for 21 times
we use "e" for 4 times
we use "l" for 2 time.
etc.
and it will write
"welcome" used for 2 times
in summary it will count the letters if how many letters same for each letters and how many words are same in each words.
i searched ı couldn't find the answer
Did you find any code to start with so that you can post an initial attempt?
i wrote counting letters. but ı did it with "goto" function ı must learn writing without "goto".
and ı couldn't find how to write counting words as my first messege
PS:"say" means >countCode:
#include<stdio.h>
#include<conio.h>
#include<string.h>
int i,j,say;
main(){
char isim[20];
clrscr();
printf("write sentence = ");
scanf("%s",isim);
for(i=0;i<strlen(isim);i++)
{
for(j=0;j<i;j++){
if(isim[i]==isim[j] || isim[i]==isim[j]+32 ||isim[i]==isim[j]-32) goto atla;}
for(j=i+1;j<strlen(isim);j++) {
if(isim[i]==isim[j] || isim[i]==(isim[j]+32) || isim[i]==isim[j]-32)
say=say+1;
}
printf("%c harfinden = %d tane var.\n",isim[i],say+1); say=0; atla:
}
getch();
return 0;
}
"isim" means >word
"atla" means jump
Let's try to get you started a little better.
Code:#include <stdio.h>
#include <limits.h>
int main(void)
{
char sentence[] = "welcome.to programming.welcome";
int i, count[CHAR_MAX] = {0}; /* initialize letter count */
/*
* Go through the sentence and increment the letter count for each letter.
*/
for ( i = 0; sentence[i]; i++ )
{
++count [ sentence[i] ];
}
/*
* Display the results.
*/
puts(sentence);
for ( i = 0; i < CHAR_MAX; i++ )
{
if ( count[i] )
{
printf("'%c' : %d\n", i, count[i]);
}
}
return 0;
}
/* my output
welcome.to programming.welcome
' ' : 1
'.' : 2
'a' : 1
'c' : 2
'e' : 4
'g' : 2
'i' : 1
'l' : 2
'm' : 4
'n' : 1
'o' : 4
'p' : 1
'r' : 2
't' : 1
'w' : 2
*/
i must learn that <limits.h> it makes works easier ı must work on words now