Character in Array to end for loop.

Hello all,
Can some please show me how I can end a for loop with a character? Right now it ends with a blank line. I want it to end when some types a '&' sign as the first charater of the array.
So if some types: &this is text. It will end or if someone just types: &
It will end, Understand?

Thanks for any help

Matt

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <iostream.h>

#define YES 1
#define NO 0 // not used

struct data {
char* text;
int bold, italic, underline;
};

void createPage ( struct data *array, int num );

int main ( void ) {
int response, i;
char buff[BUFSIZ];
struct data myStructArray[80];

// this loop in a function would be a good idea
for ( i = 0 ; i < 80 ; i++ ) {
printf( "Please enter a line of text (blank to exit): " );
fflush( stdout );
fgets( buff, BUFSIZ, stdin );
if ( strlen(buff) == 1 ) break;
// y = buff;
// strcmp(x, y);
// puts(buff);
// printf("%d", strcmp(x, y));

myStructArray[i].text = malloc( strlen(buff)+1 ); // allocate space
strcpy( myStructArray[i].text, buff );

printf( "\nDo you want text to be bold?[1/0] " );
fflush( stdout );
fgets( buff, BUFSIZ, stdin );
sscanf( buff, "%d", &response );
myStructArray[i].bold = response;

printf( "\nDo you want text to be Italics?[1/0] " );
fflush( stdout );
fgets( buff, BUFSIZ, stdin );
sscanf( buff, "%d", &response );
myStructArray[i].italic = response;

printf( "\nDo you want text to be Underlined?[1/0] " );
fflush( stdout );
fgets( buff, BUFSIZ, stdin );
sscanf( buff, "%d", &response );
myStructArray[i].underline = response;
}

createPage( myStructArray, i );
return 0;
}

void createPage( struct data *a, int num ) {
int i;
FILE* outFile;
outFile = fopen( "phaseTwo.html","w" );

/* All HTML files must start with this tag. */
fprintf( outFile,"<html>\n" );

for ( i = 0 ; i < num ; i++, a++ ) {
if(a->bold == YES) {
fprintf( outFile,"" );
}
if(a->italic == YES) {
fprintf( outFile,"" );
}
if(a->underline == YES) {
fprintf( outFile,"" );
}

/* Write to the file HTML representing a line of text. */
fprintf( outFile,"" );
fprintf( outFile,"%s",a->text );
fprintf( outFile,"\n" );

if(a->bold == YES) {
fprintf( outFile,"\n" );
}
if(a->italic == YES) {
fprintf( outFile,"\n" );
}
if(a->underline == YES) {
fprintf( outFile,"\n" );
}
}

fprintf( outFile,"</html>\n" );
fclose( outFile );
}

Did some reading, here is the answer.

if ( buff[i] == '&' ) break;

Matt

Oops ..not the answer...only does it once through..second time does not work.

I am new at this just like you...but here's a shot at it.

Code:

//declare a character array char string[80]; printf("Enter some text\n"); fflush(stdin); scanf("%s", string); if(string[0]!='&') { do stuff; }

don't forget the proper #include statements.
Use a C reference book to get that info.

essentially, you can use the string[0] in a variety of ways to test for your condition.

Hope this helps,
Mike

One question for ya Matt....

do you want the for loop to end at anytime in the string you encounter the special character? or only when the & is the first character?

if the latter, try this. It will end either when it encounters the end of the string, or when it encounters this special character.

Code:

for(i=0, string[i]!='&' || i<=strlen(string); ++i) { do stuff }

At least you see the gist of what I am trying to do.
it may be that you have to use && instead of ||. I am not the best at thinking through the logic stuff just yet.
:)

Okay...finally...

if ( buff[0] == '&' )
break;

Thanks of help Mike..

Matt

fflush(stdin) doesn't work.
use this instead.

while(getchar() != '\n')continue;