It works just fine but

This is a program we had to do for class, and it works just fine but I get a curious error message.

payroll.cpp(57) : warning C4551: function call missing argument list

To save you the trouble of having to count :p The line it's complaining about is in red, it's the payroll.close line.

Why am I getting this error, anyone know?

Code:

---

#include <iostream>
#include <fstream>
#include <cstdlib>
#include <iomanip>

using namespace std;

void createPayroll();
void createReport();

int main()
{
        char ans;

        createPayroll();

        cout << "\n\nCreate Payroll Report? <y or n>";
        cin >> ans;

        if (ans == 'y')
        {
                createReport();
                cout << "\nReport has been created\n";
        }
        return 0;
}

void createPayroll()
{
        int empNum;
        double hours, payRate;

        ofstream payroll;
        payroll.open("payroll.txt", ios::app);

        if (payroll.fail())
        {
                cout << "Error opening output file." << endl;
                exit(1);
        }
   
        cout << "Enter Employee Number (0 to quit): ";
        cin >> empNum;
        while (empNum > 0)
        {
        cout << "Enter Hours Worked: ";
                cin >> hours;
                cout << "Enter Pay Rate: ";
                cin >> payRate;
                               
                payroll << empNum << " " << hours << " " << payRate << endl;

                cout << "\n\nA record has been added.\n";
                cout << "Enter Employee Number (0 to quit): ";
                cin >> empNum;
        }
        payroll.close;
}

void createReport()
{
        int empNum;
        double hours, payRate, pay;

    ifstream payroll;
        ofstream report;

        payroll.open("payroll.txt");
        report.open("report.txt", ios::app);

        if (payroll.fail())
        {
                cout << "Error opening input file.";
                exit(1);
        }
        if (report.fail())
        {
                cout << "Error opening output file.";
                exit(1);
        }
       
        report.setf(ios::fixed);
        report.setf(ios::showpoint);
        report.precision(2);

        report << "Emp Number" << setw(12) << "Hours" << setw(12) << "Pay Rate" << setw(12) << "Pay" << endl;
        while (payroll >> empNum >> hours >> payRate)
        {
                if (hours > 40)
                {
                        pay = (((hours - 40) * payRate) * 1.5) + 40 * payRate;
                }
                else
                {
                        pay = hours * payRate;
                }
                report << empNum << setw(18) << hours << setw(12) << payRate << setw(12) << pay << endl;
        }
}

---

close is a function (to be specific, it's a member function of a class, and payroll is an instance of that class). Function calls always have a set of parentheses after them - even if there are no arguments. Add that empty set of parentheses and you're good to go.

its suppose to be

Code:

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payroll.close();

---

;)

EDIT: sean you must've answered just a sec before me! lol

Ah ha! :D