Enumeration

I am having a real hard time manipulating enumerations. What I am trying to do is make a guessing game that has a state's name in the enumeration block. The user types in a state, and the program needs to tell them if they guessed the right one. Each state is represented as a number since it's enumerated and I have the program randomly guessing numbers. I am lost on how to manipulate the enumerated data in collaberating with the random numbers that the program is using.

I hope my explanation wasn't confusing.

Any ideas would be appreciated. Thank you.

Something like so?

Code:

---

enum options { HOUSE, DOG, CAT, FRED, NUMOPTIONS };

char c_options[NUMOPTIONS][256]=
{
    "House",
    "Dog",
    "Cat",
    "Fred",
};

---

Code:

---

cout << c_options[HOUSE] << endl;

---

Will output House.

Or something slightly more robust when dealing with invalid "states".

Code:

---

#include <iostream>
using namespace std;

enum State_t
{
    STATE_1,
    STATE_2,
    STATE_3,
    STATE_4,
    STATE_5,
    STATE_6,
    STATE_7,
};//State_t

struct StateNamePair
{
    State_t m_state;
    const char *m_name;
};//StateNamePair

const StateNamePair StateNameTbl[] =
{
    {STATE_1, "STATE_1"},
    {STATE_2, "STATE_2"},
    {STATE_3, "STATE_3"},
    {STATE_4, "STATE_4"},
    {STATE_5, "STATE_5"},
    {STATE_6, "STATE_6"},
    {STATE_7, "STATE_7"},
};//StateNameTbl

const char* LookupStateName(int state)
{
    const int StateNameTbl_SZ = sizeof(StateNameTbl) / sizeof(*StateNameTbl);
   
    for (int n = 0; n < StateNameTbl_SZ; n++)
    {
        if (state == StateNameTbl[n].m_state)
            return StateNameTbl[n].m_name;
    }//for

    return 0;
}//LookupStateName

int main()
{
    const char *state_name = LookupStateName(STATE_1);

    if (state_name)
        cout << "Found name: " << state_name << endl;
    else
        cout << "Name not found." << endl;

    return 0;
}//main

---

gg

Well, if the states are invalid, I will just count them as a wrong guess.
The logic for my program is kind of like this: User types in a state. If state is equal to the program-generated number, display message, "You've got it. It took you this # of times." If state is not equal to program generated number, try again, and increment number of guesses by one.

This is what I have so far. I think I'm in the ballpark, but not fully there yet. Any ideas would be great.

Code:

---

#include <iostream>
#include <string>
#include <stdlib.h>
#include <time.h>

using namespace std;

void guess(string& input, int& computer_number);
enum block {florida, wisconsin, california};
block states;

int main() {
    srand(time(0));
    int computer_number = rand()%6;
        string input;

        cout << "Enter the state: ";
        cin >> input;

        guess(input, computer_number);

        return 0;
}

void guess(string& input, int& computer_number) {
        switch (input) {
        case florida: colors = florida;
                break;
        case wisconsin: colors = wisconsin;
                break;
        case california: colors = california;
                break;
        default: cout << "Invalid input";
        }

---

Code:

---

string input;
...
...
switch (input)

---

In a switch statement, input has to be an integer. A series of if-elseif statements does the same thing as a switch statement, so in this case use if-elseif's to compare the input to the various states.

You haven't declared a variable called colors:

Code:

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void guess(string& input, int& computer_number) {
        switch (input) {
        case florida: colors = florida;

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