'overwriting arrays' question

Lets say I wrote in a function in my program where if you select a name to delete (the name is set to: NameArray[x]). Now what I want to do is.. if that name is selected for deletion, that NameArray[x] to be renamed as '<space>' (to replace with a space). What 'method' can I use to do this. I already tried

Code:

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NameArray={' '}

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and I get a syntax error. Please provide any information to resolve this issue, any help will be appreciated. Thanks.

On the right path, you need to specify what element in the array you want to 'delete'

Code:

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array[i] = " ";

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not at a computer where i can test, silly though i can not remember if the { } are needed, just give it a test.

EDIT: just looking over your post you had the answer within ;)

Here is another example of how arrays work:

Code:

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string Names[] = {"tom", "dick", "harry"}; //initializer list
cout<<Names[0]<<endl<<endl;; //tom

Names[2] = "alice";

for(int i=0; i<3; i++)
{
        cout<<Names[i]<<endl;
}

Names[1] = " ";
cout<<Names[1]<<endl; //<a space is displayed>

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1)You can also make that array value nothing--not even a space--by doing this:

Names[1] = "";

2)The initializer list:

{"tom", "dick", "harry"}

gets its name from the fact that you can only use it to 'initialize' an array. Initializing an array means you assign it some values as at the same time that you declare the array. You can't use an initializer list after you declare an array. For instance, this doesn't work:

Code:

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string Names[3];

Names = {"tom", "dick", "harry"};

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>>the name is set to: NameArray[x]
Are you using an array of std::string or are you using an array of char[]?

If std::string, then 7stud's solution (names[x] = "") will probably be the best to clear a string; if it's char[], then you can do:

names[x][0] = '\0';

Basically that just sets the null-terminating character at the first element of the 'string', effectively making the rest of it invisible to any function that cares.