significant numbers

Hello again,
I've been searching a lot of FAQs and doing a lot of searching but I cant seem to find this one answer (maybe no one else cares :()...

The question is: how can I choose how many significant numbers are printed to screen? Meaning, I want to show .50 but my program displays .5 only and also, I want to display 2.00 but I only get 2...any ideas or good shoves in the right direction? Thanks a lot!
-Chap

oh and sorry to be a pain...but one more question...is this unnecessary? In the following, ch is an int

Code:

---

while ((ch = getch()) != ESC)
        {
                if (static_cast<char>(ch) == 'p')
                {
                        toll.payingCar();
                        cout << "A paying car!\n";
                }

---

what I'm asking about is the static_casting of ch to type char. The program works both ways, I was just wondering why it would work both ways and if I should not waste my time with the static_cast

Quote:

---

Originally Posted by Chaplin27

Hello again,
I've been searching a lot of FAQs and doing a lot of searching but I cant seem to find this one answer (maybe no one else cares :()...

The question is: how can I choose how many significant numbers are printed to screen? Meaning, I want to show .50 but my program displays .5 only and also, I want to display 2.00 but I only get 2...any ideas or good shoves in the right direction? Thanks a lot!
-Chap

---

I assume this is what you want:

Code:

---

      #include<iostream>
        #include <iomanip>
        using namespace std;

        int main()
        {
                double x = 12.123456789;
                cout<<setprecision(10);
                cout<<x;
                system("pause");
                return 0; // success return
        }

---

thanks for the answer...but it doesnt seem to have changed anything...I think the way setprecision works (tell me if I'm wrong) is if you have an overflow of numbers (.1234) but you want to chop it down to what you need (.12)...what if you need to add numbers that technically dont exist? in my program, incrementing the total dollar amount by .50 will generate a simple 1, I dont think setprecision will add a decimal and 2 zeros.

Maybe it's going to simply take some math? Only one way to find out...

Quote:

---

Originally Posted by Chaplin27

oh and sorry to be a pain...but one more question...is this unnecessary? In the following, ch is an int

Code:

---

while ((ch = getch()) != ESC)
        {
                if (static_cast<char>(ch) == 'p')
                {
                        toll.payingCar();
                        cout << "A paying car!\n";
                }

---

what I'm asking about is the static_casting of ch to type char. The program works both ways, I was just wondering why it would work both ways and if I should not waste my time with the static_cast

---

1. Since getch() is not a standard C (or C++) library function, I can't comment on what's necessary or unnecessary.

If you were using getchar(), however, the cast would be necessary to print it as a char since ch should be an int (so that you can test for the return value of EOF). Of course getchar() can't read an ESC, so it won't do you much good, but I just thought you might want to know why you might see something like that in a program

2.

Use fixed and setprecision to specify the exact number of digits after the decimal

Code:

---

#include<iostream>
#include <iomanip>

using namespace std;

int main()
{
  double x = 12.5;
  double y = 12;
  double z = 12.344;
  cout << "x = " << fixed << setprecision(2) << x << endl;
  cout << "y = " << fixed << setprecision(2) << y << endl;
  cout << "z = " << fixed << setprecision(2) << z << endl;
  return 0; // success return
}

---

Regards,

Dave

dave...greatest answer ever...thanks!and Micko thanks yet again for the help :)
-Chap

one more thing...if I have an answer of 29.8, how can I convert that to 30?

Quote:

---

Originally Posted by Chaplin27

one more thing...if I have an answer of 29.8, how can I convert that to 30?

---

If you have the function round() in your math library (part of C99 Standard library --- gcc has it) use it.

If not then you can use standard library functions ceil() and floor() (prototyped in <cmath>) as follows:
suppose we have this

Code:

---

double x, xrounded;

---

Then for positive numbers you can use this:

Code:

---

xrounded = floor(x + 0.5);

---

For negative numbers:

Code:

---

xrounded = ceil(x - 0.5);

---

Regards,

Dave

Yes, Dave Evans is absolutely right, I was in a hurry (going to swimming pool) and didn't fully understand your question.
When ios::fixed is set, floatingpoint values are printed using decimal notation.
For example

Code:

---

        #include<iostream>
        #include <iomanip>

        int main()
        {
                double x = 12.0;
                cout<<fixed<<setprecision(7)<<x;
                return 0; // success return
        }

---

wil display 12.0000000.
Thanks Dave for correcting me!
Cheers!

or seting ios flags... which can keep the settings for a whole program.

Code:

---

cout<< setiosflags( ios::fixed | ios::showpoint);

---

example:

Code:

---

#include <iomanip>
#include <iostream>
using namespace std;

main()
{
  cout << setiosflags( ios::fixed | ios::showpoint );
  double a = 2.5555;
  float b = 2;
 
  cout<< setprecision(2);
  cout<< a << endl << b << endl;
 
  return 0;
}

/*
OUTPUT:
2.56
2.00
*/

---