What's going on? Help on this please..

Code:

---

    for(;concat[a] != '\0';a++){
                for(;concat[b] != '\0';b++){
                          if(concat[a]==concat[b+2] && concat[a+1]==concat[b+3]) {
                                count++;
                                if(count>count2){
                                        count2=count;
                                        count=1;
                                        printf(" %c%c", concat[b+2], concat[b+3]);
                                        printf(" %d",count2);
                                }
                                else if(count==count2){
                                        count=1;
                                        printf(" %c%c", concat[b+2], concat[b+3]);
                                        printf(" %d",count2);
                                }
                        }
                }
      }

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I'm trying to print out the most consecutive pairs. Please Help.

Terribly sorry, its just a method from a part of a program. I'll post an example.

Input : This is another test (Another method has been placed to ignore the white space and case).
Output: (nothing happened).

Expected output to print:
th 2
is 2

I'm trying to place a check for the first pair to compare with the next pair and next till the end. It goes on until the first pair reaches the end.

Code fragments are wonderfully lacking in information -- care to provide any context or should we just try to read your mind?

what horrible indentation of the code...please indent it properly, i doubt anyone will read it the way it is now.

Sometimes edit, sometimes reply.

Code:

---

#include<stdio.h>

void foo(const char *concat)
{
#if 0 /* dangling code presumed to be part of 'foo' */
  // what is concat, really?
  // what is count?
  // what is count2?
  // what is a?
  // what is b?
  // do you realize that a+1 might be outside of concat[]?
  // do you realize that b+2 might be outside of concat[]?
  // do you realize that b+3 might be outside of concat[]?
  for ( ;concat[a] != '\0';a++ )
  {
      for ( ;concat[b] != '\0';b++ )
      {
        if ( concat[a]==concat[b+2] && concat[a+1]==concat[b+3] )
        {
            count++;
            if ( count>count2 )
            {
              count2=count;
              count=1;
              printf(" %c%c", concat[b+2], concat[b+3]);
              printf(" %d",count2);
            }
            else if ( count==count2 )
            {
              count=1;
              printf(" %c%c", concat[b+2], concat[b+3]);
              printf(" %d",count2);
            }
        }
      }
  }
#endif
}

int main(void)
{
  foo("th");
  return 0;   
}

---

[edit]

Code:

---

#include <stdio.h>

void foo(const char *text)
{
  int i, j, consecutive;
  for ( i = 0; text[i] != '\0'; i += j )
  {
      consecutive = 1;
      for ( j = 1; text[j + i] == text[i]; ++j )
      {
        ++consecutive;
      }
      printf("so far, '%c' has %d consecutive\n", text[i], consecutive);
  }
}

int main(void)
{
  foo("iii  aaammm  cccooonnnffffffuuuuuuuuussssssssssseeeeeeeeedddd");
  return 0;   
}

/* my output
so far, 'i' has 3
so far, ' ' has 2
so far, 'a' has 3
so far, 'm' has 3
so far, ' ' has 3
so far, 'c' has 3
so far, 'o' has 3
so far, 'n' has 3
so far, 'f' has 6
so far, 'u' has 9
so far, 's' has 11
so far, 'e' has 9
so far, 'd' has 4
*/

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Thanks Dave_Sinkula! It works now. Apparently your method has sparked an idea out from my mind. However, I do apologise for my post as it was my first time. Thanks! Cheers!