Question regarding the fill function.

I was wondering how to use the fill function to place leading 0's before my integer value, provided it's not of a certain size. In the program I'm writing, I'm supposed to accept a membership card number. This number can be between 1 and 999999 inclusive. The formatting is supposed to be 12-3456, but whenever the number is less than 6 digits long, the format is 00-0234, etc. I was trying to use the fill function to do so, with no luck. I've separated the number into two integers representing the first two digits and the last four, I just can't seem to get the leading zeroes. Any ideas?


- Chris

Something like this, perhaps?

Code:

---

    int no = 000456;
   
    stringstream sout;
    sout << setfill('0') << setw(6) << no;
    string s = sout.str();
    s.insert(2,"-");
    cout << s;
    cin.get();

---

Used something similar and it works great. Done my project 2 hours before the due date, and I didn't even procrasinate. What a mess =D. Thanks a bunch.