help in c++

the directions was to:
1. enter name of student into array of string; size is
60
-enter size of array
-surname first name, middle initial
2. display names
3.sort names alphabetically
4. exit program

this is what i did;

Code:

---

# include <iostream.h>
# include <string.h>
# include <conio.h>

  struct names{
    char name[20];
       
};

void bubble();


    int main(){
    bubble();
    return 0;
}


    void bubble(){
    int n;
    char temp[20];
    cout<<"How many names are you going to
insert?"<<endl;
    cin>>n;
    names * array=new names[n];


        for(int i=0;i<n;i++) {
        cout<<"Give me the name"<<endl;
        cin>>array[i].name;


    }

    for (int x=1 ; x<n ; x++)
    for (int y=0 ; y<n-x ; y++)


        if ( strcmp ( array[y].name, array[y+1].name)
> 0){
        strcpy( temp,array[y].name);
        strcpy( array[y].name, array[y+1].name );
        strcpy( array[y+1].name, temp );
    }


        for(int a=0;a<n;a++){
        cout<<"The sorted names are:
"<<array[a].name<<endl;
    }

    getch();
}

---

my proffesor told me:

i should be able to type the name, middle name, & surname into an array that has the size of 60
i used cin, i should just use c++
i should follow directions
he said all i did was 1 & 3 :(

you can use array inside another array for the 1st name and for the last name or u can use cin.getline

You're on the right track. With a little work, that struct will do it for you. I'll give you a hint.

Code:

---

struct names
{
    char first_name[20];
    //add more fields
};

---

Of course, then your sort will be a little different. You'll either need an overloaded = operator or a lot of strcpy().

Any particular reason you're using char arrays (C-strings) instead of strings?

Quote:

---

I'll give you a hint.
char first_name[20];

---

Quote:

---

the directions was to:
1. enter name of student into array of string; size is
60

---

=====

Quote:

---

Any particular reason you're using char arrays (C-strings) instead of strings?

---

Quote:

---

the directions was to:
1. enter name of student into array of string; size is
60

---

Quote:

---

my proffesor told me:
i should be able to type the name, middle name, & surname into an array that has the size of 60

---

====

This was your instruction:

Quote:

---

1. enter name of student into array of string; size is
60

---

..and you did this:

Code:

---

struct names{
    char name[20];
       
};

---

Are you supposed to use a struct? I don't think that makes sense given the instructions. It sounds like you are supposed to use a char array of size 60 to hold all three names, but then your instructions say the user is supposed to enter the size of the array? Which is it?

Quote:

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i used cin, i should just use c++

---

cin is c++, do what does that mean?