Scanf

No matter what figure I input. It come out the same figure. Please help me. I think there are some thing wrong of " scanf(%ld0". Please help me. thanks a lot.

#include <stdio.h>

long tax_in,tax_pay; //tax_in=taxable income,tax_pay=tax payable

main()

{
printf("Please input your amount of taxable income or input -9999 to exit the program.\n");


scanf ("%ld" , &tax_in);

while (tax_in !=-9999)
{
if ((tax_in>0) && (tax_in<999999))
{
if ((tax_in>0) && (tax_in<=20000))

tax_pay=tax_in*0.02;

else

if ((tax_in>20000) && (tax_in<=50000))

tax_pay=(tax_in-20000)*0.07+400;

else

if ((tax_in>50000) && (tax_in<=100000))

tax_pay=(tax_in-50000)*0.15+2500;

else

if ((tax_in>100000) && (tax_in<=999999))

tax_pay=(tax_in-100000)*0.20+10000;


printf( "Your tax payable is %ld\n", &tax_in);




}

else

printf ( "Invalid amount, please try again.\n");
printf ( "Enter taxable income: ");

scanf ("%ld" , &tax_in);

}


}

S Lee,

Look at you last line in your while:

Code:

---

printf( "Your tax payable is %ld\n", &tax_in);

---

The variable you are printing is the same variable the user entered. It should be:

Code:

---

printf("Your tax payable is %ld\n", tax_pay);

---

Also, why declare them as longs? If I remember correctly a long and an int both are 4 bytes.

Another thing, it seems like you have a few braces missing inside your while (on the nested if-else's), may wanna double check that.

{forgot that printf's don't take addresses}

printf( "Your tax payable is %ld\n", &tax_in);

You aren't supposed to pass addresses to printf. Just pass the variable itself...

printf( "Your tax payable is %ld\n", tax_in);