help with using printf()

I am using Microsoft Visual C++ V6.0 Standard Edition to compile the C code below as a standard console application. But when I run the code in the console and type some text the printf() function will not work for me when printf() is the outside of the While loop the way I have it below. Only when I move the printf() inside the While loop will I get a result. Can anyone tell me what I am doing wrong? This problem also happens when I try to use putchar(). My email is [email protected].

Code:

---

/* This is a program to count blanks, tabs, and newlines */
 
#include <stdio.h>
 
void main()
{
    int nb, nt, nl, c;
 
    nb = 0;
    nt = 0;
    nl = 0;
    while ((c = getchar()) != EOF)
    {
      if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
    }
    printf("%d %d %d\n", nb, nt, nl);
}

---

Joe

>>void main()
Visual Studio may allow this, but it's not a good idea. The language specification requires main to return int, and not doing so could cause problems.

Aside from that, the code works just fine. Are you actually signalling EOF with the ctrl+z key combination?

Unless the while loop ever sees an EOF, it won't leave the loop. Try adding a check against a newline as well.

[edit]just realized that will conflict with the loop trying to count newlines.[/edit]

try this bit of code
#include <stdio.h>

Code:

---

int main()
{
    int nb, nt, nl, c;
 
    nb = 0;
    nt = 0;
    nl = 0;
    do
    {
        c=getchar();
          if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
}while(c!='\n');

    /*
    while ((c = getchar()) != '\n')
    {
      if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
    }*/
    printf("%d %d %d\n", nb, nt, nl);
    getchar();
}

---

hope it helps

You get nothing in from your printf statement because you have not reached EOF. run the following code, type random strings, spaces and tabs then signal EOF by pressing Ctrl-z. And start writng your programs correctly, as far as your concerned main always returns an int. When your adept to know it doesn't then you'll know ;)

Code:

---

/* This is a program to count blanks, tabs, and newlines */
 
#include <stdio.h>
 
int main(void)
{
    int nb, nt, nl, c;
 
    nb = 0;
    nt = 0;
    nl = 0;
    while ((c = getchar()) != EOF)
    {
      if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
    }
    printf("%d %d %d\n", nb, nt, nl);
    getchar();
    return 0;
}

---

Quote:

---

Originally Posted by Sake

>>void main()
Visual Studio may allow this, but it's not a good idea. The language specification requires main to return int, and not doing so could cause problems.

Aside from that, the code works just fine. Are you actually signalling EOF with the ctrl+z key combination?

---

Hi,
Thanks for your reply. If I run the program and type some code and then signal EOF without hitting return, the console asks me to 'press any key to close window'. I think you are right though that the problem must be that somehow I am not actually signalling EOF.

Joe

Quote:

---

Originally Posted by ssharish

try this bit of code
#include <stdio.h>

Code:

---

int main()
{
    int nb, nt, nl, c;
 
    nb = 0;
    nt = 0;
    nl = 0;
    do
    {
        c=getchar();
          if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
}while(c!='\n');

    /*
    while ((c = getchar()) != '\n')
    {
      if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
    }*/
    printf("%d %d %d\n", nb, nt, nl);
    getchar();
}

---

hope it helps

---

Hi,
Thanks for your reply. I replaced EOF with '\n' and ran my program and it worked. So the problem must have been that I was not signalling EOF. When I run my program and hit the return I guess I am sending a carriage return and not EOF like I thought.

Joe

Quote:

---

Originally Posted by ssharish

try this bit of code
#include <stdio.h>

Code:

---

int main()
{
    int nb, nt, nl, c;
 
    nb = 0;
    nt = 0;
    nl = 0;
    do
    {
        c=getchar();
          if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
}while(c!='\n');

    /*
    while ((c = getchar()) != '\n')
    {
      if (c == ' ')
          ++nb;
      if (c == '\t')
          ++nt; 
      if (c == '\n')
          ++nl;
    }*/
    printf("%d %d %d\n", nb, nt, nl);
    getchar();
}

---

hope it helps

---

Hi,
Thanks for your reply. I executed the code above and it worked perfectly. I just started learning c and was not familiar with DO. I have a long way to go.

Joe

Quote:

---

Originally Posted by Scribbler

Unless the while loop ever sees an EOF, it won't leave the loop. Try adding a check against a newline as well.

[edit]just realized that will conflict with the loop trying to count newlines.[/edit]

---

Hi,
Thanks for your reply. Checking for a newline was one way to solve the problem. With my code, apparently the while loop never sees an EOF.

Joe

studying...............

Hi,
Thanks for you 4 consecutive replies. ( :) )

sand_man

As far as I know, getchar() and putchar() are buffered, which means that they wait for an enter before anything happens.

To get your program to read the contents of a file easily, try this in a Windows console:

Code:

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c:\>type myprog.c | myprog.exe
142 0 23

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