Array initializing to a function parameter

Hi all..I have a little situation that I'd really like to know.
I could have for example

struct Something {
int arr[7];

Something(int _arr[]) {...}
~Something() {}
};

or

int arr[5] and f(int _arr[]).

So my question goes, how would u initialize arr[] during the call of f() so that f() gets the initialized values?

I've tried normal initializing with {}:

Something strange( Something({0, 3, 6, 7, 2}) );

Compiling this causes an error. That's all i know ;) for now?
U'd be a big help with my project, thanks

you need to provide the name of the struct/class and remember to use a second set of brackets for arrays in the structure:

Code:

---

struct foo {
 int i;
 float j[3];
 };

void bar(foo f) {

 }
 
int main() {
 bar((struct foo){1, { 2.0, 3.0, 4.0 } });
 }

---

for plain arrays you should be able to do:

Code:

---

void bar(int array[]) {

 }
 
int main() {
 bar((int[]){10, 12, 3});
 }

---

hmm :confused: I copied your bar code and compiled it and I got an expression syntax error...and i'm wondering if that should work with all compilers, even with my brcc32.exe (i didn't find the version number)?

Compound literals are a new feature of C99, and there are only a couple of compilers which support it.

C++ does not have this feature
http://david.tribble.com/text/cdiffs...mpound-literal

So the safe thing is to initialise a variable with the data you want, then pass that variable to the function in question.