How to read in an integer and display it again

Hi,
I have the simple code below

Code:

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Console::WriteLine("Hello World");
int i = Console::Read();
char c =(char)i;
Console::WriteLine(c);

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After I type in '1', Writeline writes 49 back to the screen when I want it to write '1'. Anybody can help with this.
Amish

Unusual looking C++ code, but I suspect there is much more to the program than you have posted. Of interest is that 49 is the ASCII decimal value for the char '1'.

Managed C++! Yeurgh!

Apparently there's no overload for WriteLine that accepts a char as first parameter. This is not surprising, as .Net only uses UNICODE. Use wchar_t instead of char.

I would like to read in the number that I type as an integer instead of a character. Any clues?

I have no clue what you want.

You type in '1'. It writes out the UNICODE code value of the character '1', which is 49. What do you want it to do? Read '1' as an integer? No can do. Read it as String (ReadLine) and then parse it (Int32.Parse).

Maybe?

Code:

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Console::WriteLine("Hello World");
char c = Console::Read();
Console::WriteLine(c);

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That reads a single character and writes it out again, though.

Best way of course is using proper C++.

Code:

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#include <iostream>

int main()
{
  int i;
  std::cin >> i;
  std::cout << i;
}

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Quote:

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Originally Posted by CornedBee

I have no clue what you want.

You type in '1'. It writes out the UNICODE code value of the character '1', which is 49. What do you want it to do? Read '1' as an integer? No can do. Read it as String (ReadLine) and then parse it (Int32.Parse).

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Thanks. That works
Amish