MFC run application by clicking on file...

hi there,

i've written a pretty simple MFC application for viewing floating point tif images. basically, by doing file->open, i create a child window that displays the image.

what i want to do is to be able to associate these floating-point tiffs with my application, so that when i double click the file, it will run the application and open the file... at the moment it just runs the application but does not open the file.

so, all i want to happen is when the file is double clicked and the application runs... is for the OnOpen() routine to be called the same as when the user does file->open from inside the application. if you know what i mean...?

any suggestions would be greatly appreciated.
thanks.
dug.

Well there are various ways of associating a file type with a program.

In XP, you just right-click on the file, choose "Open With..." and follow the dialogs to choose your program.

In the WinApp::InitInstance() call GetCommandLine(), which returns a pointer to the command-line string for the current process. Load the file using the file name that’s contained within the 2nd set of quotes. e.g.:

"C:\Program Files\MyApp.exe" "C:\Some Folder\Dragged.jpg"

You add a registry key to HKEY_CLASSES_ROOT. More information here.

Edit: oops, I misread the question. I thought you were asking how to associate a file with your program.

thanks scarlet!

inside WinApp::InitInstance, here's what worked for me:

Code:

---

char* buff;
char* command_line = GetCommandLine();

buff = strchr(command_line, ' ');
buff++;

if (buff != NULL)
{
        pMainFrame->OpenFile(buff);
}

---

dug.