arrays doubt

I've a little doubt in arrays,

i'm trying to make a program that change, the 1st element of an array ( v[0] ) for the last one ( v[5] for example).

i call the funcion change:

Code:

---

void change(int v[], int x){
int i , t , x;
for(i=0;i<=n-1;i++){
x=v[0];
t=v[n-1];
v[0]=t;
v[n-1]=x;
}
for(i=0;i<=n-1;i++){
printf("%d\n", v[i]);
}
}

---

and i use these main:

Code:

---

int main(){
int a[SIZE]={8,5,6,9,1,3}, m=6, i;

for(i=0;i<=m-1;i++){
printf("%d\n"a[i]);
}

printf("\n\n");

change(a,m);
}

---

Can anybode tell me what's wrong in the function??
thank u, johnny!

Quote:

---

Originally Posted by j0nnyX

I've a little doubt in arrays,
i call the funcion change:

Code:

---

void change(int v[], int x){
int i , t , x;
for(i=0;i<=n-1;i++){
x=v[0];
t=v[n-1];
v[0]=t;
v[n-1]=x;
}
for(i=0;i<=n-1;i++){
printf("%d\n", v[i]);
}
}

---

Can anybode tell me what's wrong in the function??
thank u, johnny!

---

Yeah, your compiler can. Did you even try to compile that? For starters, there is no variable named n in the function. Yeah. That'll be a problem...

Quzah.

so, i should substitute n for the variable x?

yes i try to compile, and the program print 2 equal arrays, equal to the original one.

You're shadowing x that's being passed to your function by declaring a second one.

Code:

---

void change(int v[], int x){
int i , t , x;

---

You should really pay attention to your compiler warnings and errors.

Quote:

---

Originally Posted by j0nnyX

yes i try to compile, and the program print 2 equal arrays, equal to the original one.

---

No it didn't. Not that code. There is no variable n, as I've stated. It will not compile the way you've posted it.

Quzah.