Variables number of arguments error

I'm having troubles parsing a variable list of arguments... :mad:

Code:

---

#include <stdarg.h>
#include <stdio.h>

void debug_output(const char *s, ...){
        va_list arglist;
//#ifdef _DEBUG
        if(!s) return;
        va_start(arglist, s);
        fprintf(stderr,s,arglist);
        va_end(arglist);
//#endif
}

int main(){
        debug_output("Exp 0\n");
        debug_output("Exp 1: %s\n","asd");
        debug_output("Exp 2: %s %s\n","abc","def");
        debug_output("Exp 3: %d\n",1);
        debug_output("Exp 4: %d %d\n",6,7);
        return 0;
}

---

And the output:

Code:

---

Exp 0
Exp 1: XPM
Exp 2: ,PM └↕
Exp 3: 1244976
Exp 4: 1244972 1245056

---

Clearly the list isn't being well formed... Any sugestions?

Try vfprintf().

gg

You're not using va_arg(). Try replacing:

Code:

---

fprintf(stderr,s,arglist);

---

with...

Code:

---

fprintf(stderr, s, va_arg(arglist, char *));

---

Of course that only works with strings. vfprintf() is another way to go :)

Yeap, vprintf worked. Thank you :D