Simple pointer question

Isnt this how I would dereferrence a pointer

Code:

---

int *num;
...
...
int i;
i = #

---

and to assign the value in num to i

Code:

---

i = **num;

---

An example:

Code:

---

int* p = new int;
*p = 3; // Assign 3 to the space pointed to by p
int num = *p; // num == 3 now

or...

int num = 3;
int* p = # // p now points to num

---

no, it would be

Code:

---

int *num;
...
...
int i = 5;
num = &i;
...
...
int x = *num;  //to assign value POINTED TO by num to x

---

No, it's like this

Code:

---

int *num;
int i;
//The memory adress of i is stored in num.
num = &i;

---

and

Code:

---

//The memory contents pointed by num are dereferenced ONCE and placed in i
i = *num;

---

;)
//EDIT: UH!! fast posters :cool:

What about :

Code:

---

int *num;
int i;

num.val=10;
i=num.val;

---

where val is a variable within a class

a) num is a pointer to an int
b) the syntax is wrong

Code:

---

struct foo
 {
    int val;
 };
 
 int main()
 {
    foo* bar = new foo;
    bar->val = 2;
    (*bar).val = 3;
 
 delete bar;
 }

---

No!
num is a pointer to an INT.

Could be

Code:

---

class Int{
    int val;
    Int(int n=0) : val(n){}
};

Int num;
int i;

num.val=10;
i=num.val;

---

//edit: post beated again! :p

Quote:

---

Originally Posted by xErath

No!
num is a pointer to an INT.

---

Quote:

---

Originally Posted by Zach L.

a) num is a pointer to an int

---

What are we debating about? ;)

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Check the times. They posted simultaneously.

Ah, thanks; just noticed.

I'll keep my eye on post times in the future. It may be the key to the answer ;)


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