Printing an array in lines of 10.

I've tried several ways to do this but I either copy one variable 10 times or they all go on the same line. How do I display an array of 50 with 10 per line?

Here is the code I already have

Code:

---

#include <iostream>
#include <cmath>

using namespace std;
const int arraySize = 51;

int main()
{
        double alphaArray[arraySize];

        for (int i=1; i < 51; i++)
        {
            alphaArray[i]= i;      // Store a number in each array element
               
                if( i < 25)
                {

                        cout << sqrt(i) << ' ' <<endl;

                }
                else
                {
                        cout << i * 3 << endl;
                }
        }


        return 0;
}

---

any help would be appreciated.

What you need to do is only output the endl when you want the line to end, so

cout << number << " ";

ten times then

cout << endl;

Have a think about that.

I've been doing that with


cout << alphaArray[0] << sqrt(i) << ' ' ;
cout << alphaArray[1] << sqrt(i) << ' ' ;
cout << alphaArray[2] << sqrt(i) << ' ' ;
cout << alphaArray[3] << sqrt(i) << ' ' ;
cout << alphaArray[4] << sqrt(i) << ' ' ;

and it returns in garble, I've also tried to do a loop for it but no go.

Code:

---

#include <iostream>
#include <cmath>

using namespace std;
const int arraySize = 51;

int main()
{
    double alphaArray[arraySize];

    for (int i=1; i < 51; i++) // Do you really mean to start at 1 and not 0?
    {
        alphaArray[i]= i;      // Store a number in each array element
               
        if( i < 25)
        {
            cout << sqrt(i) << ' ';
        }
        else
        {
            cout << i*3 << ' ';
        }
        if( ... ) // Figure out what to put in place of the ... (hint: it involves "i")
            cout << endl;

    }


    return 0;
}

---

You only want a new line if i is a multiple of ten, which is to say, if i modulo ten is zero.

Another question is does your compiler allow a call to sqrt() with an integer argument? Mine doesn't, it has several overloaded functions, but not an integer version.

got it to work, the winning code is:

Code:

---

#include <iostream>
#include <cmath>

using namespace std;
const int arraySize = 51;

int main()
{
        double alphaArray[arraySize];

        for (int i=1; i < 51; i++)
        {
            alphaArray[i]= i;      // Store a number in each array element
               

                if( i < 25)
                {

                        cout<< sqrt(i) << " | " ;

                                        if(i % 10 == 0)
                                        {
                                                cout << endl;
                                        }
                }
                else
                {
                        cout << i * 3 << " | ";
                                        if(i % 10 == 0)
                                        {
                                                cout << endl;
                                        }
                }
               

        }


        return 0;
}

---

Quote:

---

Originally Posted by adrianxw

Another question is does your compiler allow a call to sqrt() with an integer argument? Mine doesn't, it has several overloaded functions, but not an integer version.

---

Do you mean that your compiler won't work with this? What is your compiler?

Code:

---

#include <iostream>
#include <cmath>

using std::cout;
using std::endl;

int main()
{
  cout << "sqrt(2) = " <<  sqrt(2) << endl;
  return 0;
}

---

The argument will be converted to double, since the prototype for sqrt() in math.h has a double argument.

(It works for me.)

Regards,

Dave

worked fine for me...shrug

>>> Do you mean that your compiler won't work with this? What is your compiler?

Quote:

---

Compiling...
xrap2.cpp
c:\crap2\xrap2.cpp(40) : error C2668: 'sqrt' : ambiguous call to overloaded function
c:\Program Files\Microsoft Visual Studio .NET 2003\Vc7\include\math.h(626): could be 'long double sqrt(long double)'
c:\Program Files\Microsoft Visual Studio .NET 2003\Vc7\include\math.h(578): or 'float sqrt(float)'
c:\Program Files\Microsoft Visual Studio .NET 2003\Vc7\include\math.h(200): or 'double sqrt(double)'
while trying to match the argument list '(int)'

Build log was saved at "file://c:\crap2\Debug\BuildLog.htm"
crap2 - 1 error(s), 0 warning(s)


---------------------- Done ----------------------

Build: 0 succeeded, 1 failed, 0 skipped

---

Visual Studio.NET 2003 Professional. The error it gives is fairly self explanatory.

Quote:

---

Originally Posted by adrianxw

>>> Do you mean that your compiler won't work with this? What is your compiler?



Visual Studio.NET 2003 Professional. The error it gives is fairly self explanatory.

---

Thanks for the update. I haven't used .NET for anything. I know that just because something works on my system (and has worked on all C and C++ systems that I have used since 19..) that doesn't mean that it works for everything everywhere.

Regards,

Dave