a little trouble with for loops

Hey all, I'm having a little trouble with a homework problem. Here it is:
Write a problem that creates the following pattern:

1 2 3 4 5 6 7 8 9
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7
1 2 3 4 5 6
1 2 3 4 5
1 2 3 4
1 2 3
1 2
1


Now I know that this will involve nested for loops, but every attempt I've made gives me results like:
999999999
888888888
777777777
666666666
555555555
444444444
333333333
222222222
111111111

Any ideas?

make the second loop depend on how far the first loop's gone and make it count from 1-9 (and counting down) instead of just filling the array with which value the first loop was on.

Code:

---

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
  /*Local Definitions*/
  int row;
  int col;
  int limit;
 
  /*Statements*/
    limit = 9;
    for (row = 1; row < limit; row++)
        for (col = 1; col < limit; col--)
                printf("%d", row);
                printf("\n");
               
 
 
       
   
   
  system("PAUSE");       
  return 0;
}

---

this is what I have based on that...it's wrong , I know. Help.
melee

to clerify my first post I didn't mean that the code should be counting down using -- I ment that is should shorten how high the values would be able to go, sorry if if it caused you any trouble.

something like

Code:

---

for (i=0:i<10;i++)
{
  for (j=0;j<10-i;j++)
  {
    /*stuff*/
  }
  /*stuff*/
}

---

Hi, try it likle this, it should produce the output as you're asked for.

Code:

---

#include <stdio.h>

int main(void)
{
        int y=0, z=0;

        for(y=9; y>0; y--)
        {
            for(z=1; z<y+1; z++)
            {

                  fprintf(stdout,"%d",z); /* print the numbers */

            }  /* end of nested for loop */
       
            printf(stdout,"\n");  /* print the new line */ 
        }  /* end of outer loop */
        return 1;
}

---

Any occasion I can use this code makes for a good day!

Code:

---

void O_Oy( char *o_o, int o_O )
{
        char V_V[BUFSIZ]="%s\n";
        char T_T[BUFSIZ]="%%[^%s]";
        char v_v[BUFSIZ]={0};
        char x_x[BUFSIZ]={0};

        while( o_O -- )
        {
                sprintf( v_v, T_T, o_o + o_O + 1  );
                sscanf( o_o, v_v, x_x );
                printf( V_V, x_x );   
        }
}

int main( void )
{
        char o_o[] = "1234567890";

        O_Oy( o_o, 0x9 );

        return 0;
}

---

:D

Quzah.

Quzah, I love that code...unfortunately, it is completely over my head at the moment. :D However, I'm saving it...and one day...when I'm a grown up programmer, I'll understand it...hopefully. Thanks!!

micklarko, shogun: Thank you ever so much. Shogun's code worked excellently!

melee