Hw help, compiling error.

#include <iostream>
using namespace std;

void Outputgrade(double avg);
int const SENTINEL = -1;
int main()
{
int i = -1;
double num = 0, sum = 0, avg;
do
{
i++;
sum += num;
cout <<" Please enter grades in percent (0-100) or -1 to terminate: ";
cin >> num;
while( ((num < 0) || (num >100)) && (num != SENTINEL))
{
cout << "you have entered an invalid value please re-enter: ";
cin >> num;
}
}while(num!= SENTINEL);
avg = (sum/i);

Outputgrade(double avg);
return 0;
}


void Outputgrade(double avg)
{
cout << "The average score for this midterm is :";
if(avg < 50)
cout << "F";
else if (avg <= 60)
cout << "D";
else if (avg <= 70)
cout << "C";
else if (avg <= 80)
cout << "B";
else if (avg <= 95)
cout << "A";
else
cout << "A+";

}


Thats my program that calculate the midterm average in term of a,b,c...etc.
i can't compile because of the following error.
missing ')' before type double ( at Outputgrade(double avg); )
and 'Outputgrade' :function does not take 0 parameter.
anyone could help me?

First of all, you need to read the sticky post to learn how to use code tags.

Second, you are calling the Outputgrade function incorrectly. You dont pass a type as a function parameter, just a variable. The correct way to do it would be:

Code:

---

Outputgrade(avg);

---

Quote:

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Originally Posted by bithub

First of all, you need to read the sticky post to learn how to use code tags.

Second, you are calling the Outputgrade function incorrectly. You dont pass a type as a function parameter, just a variable. The correct way to do it would be:

Code:

---

Outputgrade(avg);

---

---

SWEET thanks, i'll make sure i'll use the code tag next time,
i luv u man.