cin.ignore()

Hey guys I was sitting on Efnet irc and this kid came in saying that he needed to use cin.ignore() to block input after the first letter on a string(for a school assignment). I was just wondering if this is possible(it intriges(sp) me) and if so how would you go about it.

Hmm, seems like you would need to ignore it after its been typed..

odd..

It intrigues(sp) me also.

http://cplusplus.com/ref/iostream/istream/ignore.html

Code:

---

// istream ignore
#include <iostream>
using namespace std;

int main () {
  char first, last;

  cout << "Enter your first and last names: ";

  first=cin.get();
  cin.ignore(256,' ');

  last=cin.get();

  cout << "Your initials are " << first << last;

  return 0;
}

---

If I wanted to have the option to have 3 names, how would I make it skip the last name, if the person has only 2 names?

I tried to make it like this, but it only works where there are 3 names.

Code:

---

int d = 0;
char a, b, c;

while (d == 0)
{
cout << "Inset your name ";

a = cin.get();
cin.ignore(30, ' ');
b = cin.get();
cin.ignore(30, ' ');
c = cin.get();

cout << endl << "Your intials are: " << a << "." << b << "."<< c << ".\n\n";

---

explicitly ask the user if they want to enter a first name/last name/other name, and if the answer is yes, then get their input, otherwise, move on. Alternatively, input the name as a single string and parse the string into the first name/middle name/last name/honorary name/etc" based on spaces between the "names".

I would actually keep your as is, but then check to see if c is a newline character. If c is a '\n' then they only have two names.

By the way, are you certain that you need to make multiple calls to ignore() like that?

I'm pretty new to programming, so I have no idea if I need to do it like this.

I have a new problem. Now it works with 2 names, but not 3 :(

Here is the code

Code:

---

main()
{
int d = 0;
char a, b, c;

while (d == 0)
{
cout << "Inset your name ";

a = cin.get();
cin.ignore(30, ' ');
b = cin.get();
if (!(c = '\n'))
{
cin.ignore(30, ' ');
c = cin.get();
}

cout << endl << "Your intials are: " << a << "." << b;

if  (!(c = '\n'))
cout << "."<< c << ".\n\n";
else
cout << ".\n\n";
}
        return 0;
}

---

And how do I clear the char variables, when it returns in the while loop?

Kinda, but no. Plus you don't need the infinite loop. Additionally, I was playing with it, ignore() is the most retardedly useless function ever.

Code:

---

#include <iostream>

int main(void) {
  bool done = false;
  char a, b, c;

  while(!done) {
    std::cout << "Inset your name ";

    a = cin.get();
    std::cin.ignore(30, ' ');
    b = std::cin.get();
    std::cin.ignore(30, ' ');
    c = cin.get();

    if(c == '\n')
      std::cout << std::endl << "Your intials are: " << a << "." << b << std::endl;
    else
      std::cout << std::endl << "Your intials are: " << a << "." << b << "."<< c << std::endl;

    std::cout << "continue?";
    done = (std::cin.get() == 'y')?false:true;
  }

  return 0;
}

---

Ah hah! I've learned when something seems useless, you are using it wrong.

http://www.augustcouncil.com/~tgibso...al/iotips.html

For those interested how to use ignore().