is there any easy way????

was wondering if there is any easy way to have mutiple deposits
with only declaring one variable

Code:

---


while (month >= 1)////start loop
        {
                cout <<"Please enter total deposits per month  $: ";
                cin >> dep;

---

in the above example how would someone enter

40.00 160.00 200.00

as individual deposits without using an array I done it before but cant remember how??? :confused:

Well the loop will naturally go round 3 times.
cin just reads what it needs to (say 40.00) and leaves the rest of the input for something else.
So next time, cin reads 160.00
etc etc

I don't know how you're gonna use those numbers,
so don't know if this will solve it

Code:

---

totalDeposit = 0;
while ( cin >> deposit )
    totalDeposit += deposit;

---

Quote:

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Originally Posted by alphaoide

I don't know how you're gonna use those numbers,
so don't know if this will solve it

Code:

---

totalDeposit = 0;
while ( cin >> deposit )
    totalDeposit += deposit;

---

---

perhaps you should try running your code before you suggest it to others :rolleyes:
while( cin >> deposit ) is a bad idea.

>perhaps you should try running your code before you suggest it to others
Perhaps you should try running someone else's code before correcting them.

>while( cin >> deposit ) is a bad idea.
I have an idea. You tell me why you think this is a bad idea and I'll tell you why you're wrong. :)

Yeah, Bjarn Stroustrup's technical FAQ uses the same code. I doubt he would do that if it was a "bad idea".

>Perhaps you should try running someone else's code before correcting them.
I did, the while cin loop never terminates. It will be pretty difficult to process the data if you never stop taking it :)

>You tell me why you think this is a bad idea and I'll tell you why you're wrong. :)
see above.

Quote:

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Originally Posted by bithub

Yeah, Bjarn Stroustrup's technical FAQ uses the same code. I doubt he would do that if it was a "bad idea".

---

In many sitiuations its a good idea, in the example given above it was a bad idea. The above example would never (properly) terminate from the input accumulation part. The code that followed, which actually processes the data, isnt reached.

hi dazed,
maybe this will assist??

was wondering if there is any easy way to have mutiple deposits
with only declaring one variable

Code:
short month = 0; //counter
float dep = (float)0.0; //user prompt
float balance = (float)0.0; //accumulator


while (month <= 2)////start loop
{
cout <<"Please enter total deposits per month $: ";
cin >> dep;
balance = balance + dep; //accumulate balance
month = month + 1; //increment counter
}

cout << "Balance is: $" << balance << endl;

>I did, the while cin loop never terminates.
Sure it does. If there's an error or if end-of-file is reached. Naturally, after the loop it would be a good idea to check and see which of those it was and an informative prompt before the loop is always nice. ;)

Code:

---

#include <iostream>

using namespace std;

int main()
{
  int n;
  int sum = 0;

  for ( int i = 0; i < 3; i++ ) {
    cout<<"Enter a series of numbers followed by EOF: ";

    while( cin >> n )
      sum += n;

    if ( !cin.eof() ) {
      cerr<<"Something bad happened"<<endl;
      break;
    }
    else {
      cout<<"The total is: "<< sum <<endl;
      cin.clear();
    }
  }
}

---

>The above example would never (properly) terminate from the input accumulation part.
Only if your idea of "properly" doesn't include reaching the end-of-file, and that's a stylistic choice.

you could just ask them how many deposits theyd like to make

Code:

---

cout << "How many deposites would you like to make? :  ";
cin >> numofdep;

while ( numofdep != 0 )
{
    cout << endl << endl;
    cout << "Enter a Deposit Amount  : ";
    cin >> dep;
    balance +=dep;
    numofdep--;
}

cout << "Your Current Balance is  $" << balance << endl;

---

thats my suggestion :)

How is eof() generated for cin? I always thought you have to hit ctrl-c, but that (as far as I know) quits the program without giving it a chance to process data.

**EDIT**
JarJarBinks, you could have just used a for loop... they tend to be easier to understand then whiles when you're looping a set number of times.

yea i was gonna use a for loop, but he started up
there with a while so i figured i wouldnt stray from anything that
he couldnt possibly understand, and if he understands for loops
then he can convert it himself :).

Quote:

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How is eof() generated for cin?

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ctrl-D in linux, and ctrl-Z in windows.

Quote:

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Originally Posted by Salem

Well the loop will naturally go round 3 times.
cin just reads what it needs to (say 40.00) and leaves the rest of the input for something else.
So next time, cin reads 160.00
etc etc

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Hehe, sorry to go offtopic, but man your avatar is so awesome. :D

Did you actually create that yourself??

Well, at least it's true! :D