Kill me too

Can anyone figure out what this means and why it wont compile?


Compiler: Default compiler
Building Makefile: "C:\Dev-Cpp\My C++ Work\Makefile.win"
Executing make...
make.exe -f "C:\Dev-Cpp\My C++ Work\Makefile.win" all
g++.exe -c Untitled4.cpp -o Untitled4.o -I"C:/Dev-Cpp/include/c++/3.3.1" -I"C:/Dev-Cpp/include/c++/3.3.1/mingw32" -I"C:/Dev-Cpp/include/c++/3.3.1/backward" -I"C:/Dev-Cpp/lib/gcc-lib/mingw32/3.3.1/include" -I"C:/Dev-Cpp/include" ../include/conio.c -nostdlib

g++.exe: cannot specify -o with -c or -S and multiple compilations

make.exe: *** [Untitled4.o] Error 1

Execution terminated

g++.exe: cannot specify -o with -c or -S and multiple compilations

It means that you are calling g++ with the -o, -c, or -S option when you are trying to do multiple compilations.

Quote:

---

Originally Posted by man gcc

-o file
Place output in file file. This applies regardless to whatever
sort of output is being produced, whether it be an executable file,
an object file, an assembler file or preprocessed C code.

Since only one output file can be specified, it does not make sense
to use -o when compiling more than one input file, unless you are
producing an executable file as output.

---

you cant compile 2 source files (as you are doing above) into an object file. You need to compile them individually (using -c) into .o files then link them into an executable OR compile them into an executable nameing it with -o name (and excluding -c)

does it matter what order the things are compiled in?

>> does it matter what order the things are compiled in?
Nope.

gg