implicit type casting

Suppose I have

Code:

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int x;
int y;
double a;
double z;
a=<static_cast>(x)/y;  // does this implicitly cast y to double
a=z/y;                        // does this implicitly cast y to double

---

I think it does. In Java it does but I am not sure about C++

Code:

---

static<cast>(x)/y;

---

or

Code:

---

<static_cast>(x)/y;

---

are wrong. Did you mean:

Code:

---

static_cast<double>(x)/y;

---

or something else?

If so, then I think yes, x is explicitly casted, and y is implicitly casted because the other operator argument is a double.

>In Java it does but I am not sure about C++
The result of an expression has the same type as the longest floatiest operand.

Thanks for the replies :)
:p

while we are on this topic.. i was taking a #2 ealier today.. and I was thinking about c++ programming.. and then i was thnking... "Is it necessary to typecast whilst using STL...???" Like.. if you divided two templated integers... would the template perform integer or floating point division...??

>i was taking a #2 ealier today..
Too much information.

>Is it necessary to typecast whilst using STL...???
If the situation warrants it, yes. But if you're using things properly these situations will be few and far between.

>Like.. if you divided two templated integers...
Can you show an example of what you mean?