*NOOB* attempt to make a calc prog

im not even half way through my book yet but i figured wat the hell ill give making a calc a try while i was on vaction. Also i would like to say i did this in a notebook didnt have a pc or nething to compile it on *sigh* neway here the code

Code:

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#include <stdio.h>

int x
int y
int add_num(int x, int y)
int sub_num(int x, int y)
int mutli_num(int x, int y)
int divid_num(int x, int y)

    int add_num = +=;
    int sub_num = -=;
    int multi_num = *=;
    int divid_num = /=;
{
    int result;
    result = x"+=,-=,*=,/="y;
    return result;
}
int main()
{
char name[200]
int sum;

sum =  add_num,sub_num,multi_num,divid_num(x,y);
printf("input:">>name>>\n");
printf("result: %d \n",sum);

  system("PAUSE");       
  return 0;
}

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i think it was a decent attempt for a noob such as my self...but neway could someone lend me a hand here??????

So many errors so little time ;)

Code:

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int x
int y

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Avoid the use of global variables when you can simply pass them

Code:

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int add_num(int x, int y)
int sub_num(int x, int y)
int mutli_num(int x, int y)
int divid_num(int x, int y)

---

Forgot the semi colons at the end of the lines

Code:

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    int add_num = +=;
    int sub_num = -=;
    int multi_num = *=;
    int divid_num = /=;

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Ain't gonna work

Code:

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{
    int result;
    result = x"+=,-=,*=,/="y;
    return result;
}

---

Where is the function header? The result = line is totally invalid

Code:

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sum =  add_num,sub_num,multi_num,divid_num(x,y);

---

Won't do what you think it'll do

Code:

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printf("input:">>name>>\n");

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Won't do what you think it'll do.

Code:

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C:\Documents and Settings\moi>gcc dumb.c -std=c99 -Wall -pedantic
dumb.c:4: syntax error before "int"
dumb.c:5: syntax error before "int"
dumb.c: In function `add_num':
dumb.c:7: parse error before "int"
dumb.c:11: parameter `sub_num' is initialized
dumb.c:11: conflicting types for `sub_num'
dumb.c:7: previous declaration of `sub_num'
dumb.c:11: parse error before '-=' token
dumb.c:6: parm types given both in parmlist and separately
dumb.c:16: parse error before string constant
dumb.c: In function `main':
dumb.c:22: warning: ISO C forbids nested functions
dumb.c:22: syntax error before "int"
dumb.c:24: `sum' undeclared (first use in this function)
dumb.c:24: (Each undeclared identifier is reported only once
dumb.c:24: for each function it appears in.)
dumb.c:24: `sub_num' undeclared (first use in this function)
dumb.c:24: `multi_num' undeclared (first use in this function)
dumb.c:24: warning: implicit declaration of function `divid_num'
dumb.c:24: `x' undeclared (first use in this function)
dumb.c:24: `y' undeclared (first use in this function)
dumb.c:24: warning: left-hand operand of comma expression has no effect
dumb.c:24: warning: left-hand operand of comma expression has no effect
dumb.c:24: warning: left-hand operand of comma expression has no effect
dumb.c:25: `name' undeclared (first use in this function)
dumb.c:25: stray '\' in program
dumb.c:25:26: warning: multi-line string literals are deprecated
dumb.c:25: `n' undeclared (first use in this function)
dumb.c:25: parse error before string constant
dumb.c:25: stray '\' in program
dumb.c:26:22: warning: multi-line string literals are deprecated
dumb.c:28:16: warning: multi-line string literals are deprecated
dumb.c:28:16: missing terminating " character
dumb.c:25:26: possible start of unterminated string literal

C:\Documents and Settings\moi>

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Code:

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#include <stdio.h>
 
int x
int y
int add_num(int x, int y)
int sub_num(int x, int y)
int mutli_num(int x, int y)
int divid_num(int x, int y)
 
int add_num = +=;
int sub_num = -=;
int multi_num = *=;
int divid_num = /=;
{
int result;
result = x"+=,-=,*=,/="y;
return result;
}

---

As far as I can tell you are trying to make a set of functions. The way you have it laid out won't work. You have to match the routines the function is made of with the declarations. That should be:

Code:

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int x;
int y;
// Placed code to right for smaller size
int add_num(int x, int y) {int add_num = +=;}
int sub_num(int x, int y) {int sub_num = -=;}
int mutli_num(int x, int y) {int multi_num = *=;}
int divid_num(int x, int y) {int divid_num = /=;}

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The section with the result is not used so I didn't make changes to that.

The next error I see is this:

Code:

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sum = add_num,sub_num,multi_num,divid_num(x,y);

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That isn't going to do what you expect. Since I'm assuming you want the sum from adding all of those, here's what you might want to try:

Code:

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sum = add_num(x,y) + sub_num(x,y) + multi_num(x,y) + divid_num(x,y);

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To output a string, change:

Code:

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printf("input:">>name>>\n");

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to:

Code:

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printf("input: %s \n", name);

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Oh and add a semicolon to this:

Code:

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char name[200]

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Hope I got everything but I may have missed something.