Newb Question - Cant convert Char[41] to Char

Hi All,

I am new to this forum and to C++ programming. But still I have managed my program to error :p.

Can someone tell me what is wrong with this code?!

Code:

---

void main()
{
        char User[UserMaxLength];
        print_header();
        User = get_user();
        printf("%s@!localhost [#]", User);
        return;
}

char get_user()
{
        char Temp[UserMaxLength];
        scanf("Gebruikersnaam: %s", &Temp);
        return Temp;
}

---

The error I get is:

Code:

---

C:\Program Files\Microsoft Visual Studio\MyProjects\Kernel\KK006b\KK006b.cpp(16) : error C2440: '=' : cannot convert from 'char' to 'char [41]'
        There are no conversions to array types, although there are conversions to references or pointers to arrays
C:\Program Files\Microsoft Visual Studio\MyProjects\Kernel\KK006b\KK006b.cpp(31) : error C2440: 'return' : cannot convert from 'char [41]' to 'char'
        This conversion requires a reinterpret_cast, a C-style cast or function-style cast

---

Any help would be greatly appreciated

Kalkran

Your return type is char. You are trying to return an array. the types dont' match so your getting an error. You want to return a pointer to the array.

As a start, use "int main()" not "void main()". If you need an explanation, have a look at the FAQ.

You cannot assign an array this way. For simplicity, I would suggest passing the array you need your data in to your get_user function and removing the temp variable.