Ok I have an array but I need to get a char array and make it actually equal the name of the array and use it accordingly. For example.
int hello[3];
char nameofarray[]="hello";
I want it to make it so that I can call nameofarray by using something like:
nameofarry[]
Is there anyway to do something like this? I know its kinda far fetched but it would really help me out.
im not sure about everyoen else, but i read your post a few times, and im not sure what your trying to say..?
what do you want to do with nameofarray ?
same here.
This line confuses me :
what are you trying to accomplish here? are you looking for a way to type the contents "nameofarray"? or maybe let the length of "nameofarray" array equal "hello" array?Code:int hello[3];
please re-phrase your question if possible
It appears as if you wish to select an array to use dynamically through a single name, nameofarray. In other words, a map with the name of the array as the key and the address of the array as the value. This is possible, though not nearly as easy as you might like. Here is one way to go about it.
Code:#include <stdio.h>
#include <string.h>
struct map {
char name[BUFSIZ];
int (*array)[3];
};
int map_index(const char *name);
int main()
{
int a[3] = {0};
int b[3] = {0};
struct map nameofarray[] = {
"a", &a,
"b", &b
};
int which = map_index("a");
if (which != -1) {
*(nameofarray[which].array)[0] = 10;
printf("a[0]: %d\n", a[0]);
printf("b[0]: %d\n", b[0]);
}
return 0;
}
int map_index(const char *name)
{
if (strcmp(name, "a") == 0) {
return 0;
}
else if (strcmp(name, "b") == 0) {
return 1;
}
else {
return -1;
}
}
Since I, like everyone else, have no idea what you're trying to do, I thought you might have some fun with this...Code:struct array
{
char *name;
size_t size;
char *data;
};
Quzah.
Err ok let me try to explain it better:
I have lets say 3 integers.
int x1;
int x2;
int x3;
Now I have a string. Lets call this string nameofint:
char nameofint[2];
I ask for an input from the user about what integer they want. The user then picks x1, x2, x3. Now nameofint is equal to x1, x2, or x3. So I wanna be able to make the int that the user picked equal another int that we will call uselessint.
int uselessint=0;
uselessint=nameofint;
Since nameofint equals either x1, x2, or x3. I want it to take the value from the integer the user inputs and put it into uselessint.
This isn't for dos this is actually for a very unknown device which i just felt like programming for while I was bored.
so something like thsi(without the x1,x2,x3)with x1,x2,x3Code:int array[3];
printf("Enter 3 numbers(integers)\n");
scanf("%d %d %d",&array[0],&array[1],&array[2]);
}
Code:int x1,x2,x3,array[3];
printf("Enter 3 numbers(integers)\n");
scanf("%d %d %d",&x1,&x2,&x3);
array[0]=x1;
array[1]=x2;
array[2]=x3;
Something more like this:
int x1=5,x2=3,x3=4,
char nameofint[3];
printf("Enter name of integer\n");
gets(nameofint);
int uselessint;
uselesss=nameofint;.//I want uselessint to equal 5 if user types in x1, 3 if he types x2,
//and 4 if he types in x3
The easiest way to do something like that is like Princeton suggested.
Code:#include <stdio.h>
int main(void)
{
int x1 = 5, x2 = 3, x3 = 4;
char nameofint[3];
int i, uselessint;
struct
{
char *name;
int *pvar;
} map[] = { { "x1", &x1 }, { "x2", &x2 }, { "x3", &x3 } };
printf("Enter x1, x2, or x3: ");
fgets(nameofint, sizeof(nameofint), stdin);
nameofint[2] = '\0'; // Get rid of the \n
for(i = 0;i < 3;++i)
if(!strcmp(map[i].name, nameofint))
break;
if(i == 3)
{
puts("That variable name isn't recognized.");
exit(1);
}
uselessint = *map[i].pvar;
printf("uselessint is %d\n", uselessint);
return 0;
}
Quote:
itsme:~/C$ ./map
Enter x1, x2, or x3: x1
uselessint is 5
itsme:~/C$ ./map
Enter x1, x2, or x3: x2
uselessint is 3
itsme:~/C$ ./map
Enter x1, x2, or x3: x3
uselessint is 4
itsme:~/C$ ./map
Enter x1, x2, or x3: foo
That variable name isn't recognized.
itsme:~/C$
You'd be using hash tables. Personally I would implement it with a struct:
Then you can set the name and value of each element in the table. After that you can use a for loop to search for values.Code:struct hash {
char name[10];
int value;
} hashtable[3];
I think I get what he's saying.
You can do it like this:
(Notice I didn't use any string.h functions for compatibility for his "unknown device"'s compiler, yes I know that strcmp and most string.h functions are ANSI C, but not every compiler's ANSI :))Code:int main(void)
{
int x1,x2,x3,uselessint;
char nameofint[2];
gets(nameofint);
if(nameofint[0]=='x'&&nameofint[1]=='1'&&nameofint[2]=='\0')
{
uselessint=x1;
}
if(nameofint[0]=='x'&&nameofint[1]=='2'&&nameofint[2]=='\0')
{
uselessint=x2;
}
if(nameofint[0]=='x'&&nameofint[1]=='3'&&nameofint[2]=='\0')
{
uselessint=x3;
}
return 0;
}
Sorry if you mean "on-the-fly variable names", but if you didn't, hope this helps ;).
> gets(nameofint);
Nope
Read the FAQ / many other posts
> Notice I didn't use any string.h functions for compatibility for his "unknown device"'s compiler
Huh?
Any compiler omitting string.h ceases to be a C compiler of any description IMO
>>Any compiler omitting string.h ceases to be a C compiler of any description IMO
A freestanding implementation is not required to supply string.h. If this "unknown device" uses such an implementation then one cannot assume the existence of string.h.
And what about the inexcusable gets() - will the free standing implementation provide that, and not string.h?
Possibly, it is up to the implementation at that point. However, my comment was not concerning Axpen's code but your statement that a compiler which omits string.h is not a C compiler "of any description", which is false because a freestanding implementation is not required to support string.h. Of course, you also said IMO so my reply was meant to give additional information to readers rather than to correct you. A statement of opinion can be inaccurate and still be entirely correct. :)Quote:
Originally Posted by Salem