simple thread signaling question

Just messing around with signals and i have a question...
in my code i have kill(getppid(),SIGUSR2); 3 times but it only gets called once. Why and how can it get called more than once?
thanks

#include <iostream>
#include <signal.h>
#include <sys/types.h>
#include <signal.h>

using namespace std;

static int alarm_fired = 0;
void ding (int sig)
{
alarm_fired = 1;

}

void you (int sig)
{
cout<<"second signal"<<endl;

}

int main(int argc, char *argv[])
{
pid_t pid;

cout<<"Alarm Application"<<endl;
signal (SIGUSR1,ding);
signal (SIGUSR2, you);

pid = fork();

switch(pid) {
case -1:
cout<<"error"<<endl;
case 0:
sleep(5);
kill(getppid(),SIGUSR1);
kill(getppid(),SIGUSR2);
kill(getppid(),SIGUSR2);
kill(getppid(),SIGUSR2);
exit (0);
}

cout<<"waiting for alarm"<<endl;


pause();
if(alarm_fired) cout<<"ding"<<endl;

cout<<"done"<<endl;


return 0;
}

code tags pls and might want to break out of your switch statement

Code:

---


switch(pid) {
case -1:
cout<<"error"<<endl;
break;//need this so one case doesn't go though another
case 0:
sleep(5);
kill(getppid(),SIGUSR1);
for(int i = 0, i<4,i++)//try this too
{
kill(getppid(),SIGUSR2);
}
exit (0);
}

---

What is diffrent about what you wrote than mine other than you call your kill 4 times instead of the 3?

Your working with signals but you don't know hoy do break down a simple for loop.

Code:

---

for(int i=0,i<4,i++)
{
//i is less than 4 eg 3 cause it is an integer
}

---