reversing elements in array

I've been trying to figure out how to reverse the elements in my array. But im drawing a blank. Any help would be greatly appreciated.

Code:

---


  #include <iostream>
using namespace std;
void reverse(int a[],int size );//prototype
int main()
{

 
 const int size=10;
int a[size]={1,2,-3,-4,-5,-6,7,8,-9,10};


 reverse(a,size);//call

  return 0;

}


 void reverse(int a[], int size) //reverse order of elements in array
 {
   
        for(int i=0;size<i;i++){
     
          cout<<a[i];
        }
       
         


       
                 
               
 }

---

Well, I'll give you a hint:

You still have the same number of elements right?
You might want to look at using the '--' (decrement) operator and start your counter not at zero but a different value.

Hope that helps!

Nick.

Ok, what you said made a lot of sense and I altered the code but now I get this inifinite loop!

Code:

---


    void reverse(int a[], int size) //reverse order of elements in array
 {
   
        for(int i=size;size>0;--i){
     
          cout<<a[i];
        }

---

A little hint on why this may be occuring would be appreciated. thanks.

a little hint: if you have size elements in your array, they are indexed from 0 to size-1

I'm thinking something like this:

Code:

---

void Reverse(int *Array,int Size)
{
        int LastIndex=size-1;
        int TempInt=0;

        if (!Array)
                return;

        for (int Loop=0;Loop<=(LastIndex/2);Loop++)
        {
                TempInt=Array[Loop];
                Array[Loop]=Array[LastIndex-Loop];
                Array[LastIndex-Loop]=TempInt;
        }
}

---

I think it will work. To me it seems like the most logical way, but it's probably not the most efficient way.

Basically it works by looping through the first half of the array and swapping each element with its far counterpart.

Quote:

---

Originally Posted by dantestwin

Ok, what you said made a lot of sense and I altered the code but now I get this inifinite loop!

Code:

---


    void reverse(int a[], int size) //reverse order of elements in array
 {
   
        for(int i=size;size>0;--i){
     
          cout<<a[i];
        }

---

A little hint on why this may be occuring would be appreciated. thanks.

---

Your infinite loop is because of the test condition in the for loop. Replace "size > 0" with "i > 0" and it will work. Oh yeah, in the body of the loop, replace "a[i]" with "a[i-1]" to access the correct element. You've got everything right.

I got it to work. Thanks Nick.