C++ GOLF (unjustified words)

First was a PERL golf, then a PHP golf (when I found and partook in it). Since this section seems to be dead and going no where I'll host a game of golf.

Remember you need to be able to explain your solution to others so dont waste coding time googling for the perl solutions.

ALL ENTRIES MUST BE IN BY MONDAY MAY/31/2004 12:pm central time
PM me your answer function.

Challenge
There are two columns of words. Left-justify the left column, and right-justify the right column, then squeeze as many spaces as possible out from between them while keeping at least one space on every line and keeping the justifications.

So with the function input:

Code:

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waf zrsea
abdef sedrgf
a warfhjik

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Your function should return:

Code:

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waf    zrsea
abdef sedrgf
a  warfhjik

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Challenge Rules
Input will be in a single string, no more than 10 lines, with two words separated by one space. Maximum word length is 10. Output should be the same but with "(space)+" instead of "(space)".

Challenge Specific Requirements
1) Function will take one parameter, a string
2) Function will return a string


C++ Golf Rules
It's pretty simple if you haven't played code golf before; shortest solution in characters that solves the challenge and meets the challenge rules wins.

1. Solutions in C/C++ only. Free to use classes, but it will likely increase your code. ++ has been added simply for header librarys
2. You can only use the standard C/C++ headers
3. Because C++ often has one shortest solution, only post your golf score until the round is declared over.
2. Your solution must be contained in a single function and your solution must be contained within the scope of the function (i.e. defining vars outside your function and using 'global a,b,c;' would not be ok.)
3. You golf score includes the function definition and all spaces. i.e.
#234567890123456
string j(string s) {} # golf score of 15


HAVE FUN - Even if you dont think you'll win have a go and see how you shape up.

So in C, you would have

Code:

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char *input = "waf zrsea\n"
              "abdef sedrgf\n"
              "a warfhjik\n";

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That is, one string containing pairs of words separated by a space, and delimited with a newline?
Is there always a newline at the end of the last line?

> 3. Because C++ often has one shortest solution, only post your golf score until the round is declared over.
If someone posts a better score, can you still work on the problem up to the deadline to see if you can still beat your previous best?

Quote:

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Originally Posted by Salem

So in C, you would have

Code:

---

char *input = "waf zrsea\n"
              "abdef sedrgf\n"
              "a warfhjik\n";

---

That is, one string containing pairs of words separated by a space, and delimited with a newline?
Is there always a newline at the end of the last line?

---

No. There is not a /n at the end of the string, just the middle.

Quote:

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> 3. Because C++ often has one shortest solution, only post your golf score until the round is declared over.
If someone posts a better score, can you still work on the problem up to the deadline to see if you can still beat your previous best?

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Yes, until the deadline you may revise your solution until you are happy.

Hmpf, not really a proper line is it then, the last one?

tis the rules.

1) Function will take one parameter, a string
2) Function will return a string
And what are the acceptable definitions of string in C?

So the idea is to create a source file to do this with the smallest footprint?

When is the deadline?

Deadline was
> ALL ENTRIES MUST BE IN BY MONDAY MAY/31/2004 12:pm central time
I submitted a score of 249, but never heard of anything as the deadline past...

oh, sorry. I was scanning this for deadlines, and I didn't see results, so I figured it was still going. I guess I didn't see them because they were in big uppercase letters right in front of my face :p

This looks like a really cool contest.... when are you guys going to do this again??!

I'd really like to get in on the next round of c++ golf.. :)

Well, here's my entry I submitted long ago..

Code:

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#include <stdio.h>
#include <string.h>

void g(char*i,char*o){
int m=0,l=0,x;char *p=i,*q;
while(x=strcspn(p,"\n")){m=x>m?x:m;p+=x+(p[x]!=0);l++;}
memset(o,' ',l*++m);o[l*m]='\0';p=i;
while(q=strchr(p,' ')){x=strcspn(q,"\n");
strncpy(o,p,q-p);strncpy(o+m-x,q+1,x);o+=m;p=q+x+(p[x]!=0);}
}


int main ( ) {
    char *i1 = "WAF zrsea\n"
              "ABDEF sedrgf\n"
              "A warfhjik\n";
    char *i2 = "waf zrsea\n"
              "a z\n"
              "aaaaaaaaa a\n"
              "z zzzzzzzzz\n"
              "a warfhjik";
    char buff[1000] = { 0 };
    g(i1,buff);
    printf( "%s--\n%s", i1, buff );
    printf("====\n");
    g(i2,buff);
    printf( "%s\n--\n%s\n", i2, buff );
    return 0;
}

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