PowerOf Function

Code:

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/* Title: c5 Review 9 (c05r09) */
#include <iostream.h>

// ----------------------------------------

void Introduction()
{
IGNORE THIS PART
}

// ----------------------------------------

double PowerOf(double x, int n)
{
CODE NEEDED HERE
        return ();
}

// ----------------------------------------

int main()
{
        double x;
        cout << "Enter the base number: ";
        cin >> x;

        int n;
        cout << "Enter the exponent: ";
        cin >> n;

        PowerOf(x, n);
        return(0);
}

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I need help figuring out how to get a number to a power and it displaying the results. What I mean is, I define x as 2 and say n as 3. That would be 2^3, or the number 8. Inside the PowerOf() function, I can't figure out the code to do that. I know it has something to do with a for loop though.

>I can't figure out the code to do that.
How would you do it on paper? Or with a calculator? Once you know that the code for such a simple function practically writes itself.

I know how to do it on the calculator, and on paper, I just can't get the for statement to give me what I want. It's probably a really simple 3-4 line code I'm just dancing around. Help?

>I just can't get the for statement to give me what I want
...

Code:

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double PowerOf ( double base, int n )
{
  double ret = 1.0;

  for ( int i = 0; i < n; i++ ) {
    ret *= base;
  }
 
  return ret;
}

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