pointer with isspace()

Code:

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#include <ctype.h>

int isspace(int c);

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if I would use a pointer into isspace function it should be an int or char pointer?

Code:

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if (isspace(*mypointer))
...

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why not try yourself?

it should be int, however if you use char the program will work, but the compiler will give you a warning:

Code:

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assignment from incompatible pointer type

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thanks

Code:

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#include <stdio.h>
#include <string.h>
#include <ctype.h>

void main()
{
        char *p;
        char k[] = "your string here";
        p=&k;
        while(!isspace(*p++));
        printf("%s",p);
       
}

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OUTPUT: string here

I cant understand it.

printf("%s",p);
shouldnt be printf("%s",*p); ?

char *p;
shouldnt be int *p; ?

so, if change it BCC55 says:

Code:

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Error E2342 teste.c 9: Type mismatch in parameter '__s' (wanted 'const signed char *', got 'int') in function main

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Quote:

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void main()

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Should be

Code:

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int main(void);

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Quote:

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p=&k;

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should be

Code:

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p = k;

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or

Code:

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p = &k[0];

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Code:

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#include <stdio.h>
#include <string.h>
#include <ctype.h>

int main(void)
{
  char *p;
  char k[] = "your string here";
  p=k;
  while(!isspace(*p++));
  printf("%s",p);
  return 0;
}

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Will output

Quote:

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string here

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char *p;
shouldnt be int *p; ?

if the pointer is int it do not point to the string

it SHOULD NOT be an int pointer doing so will printout every 4th character. However if you are getting warnings/errors from the isspace() call then you can use:

Code:

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while(!isspace((int)*p++));

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Which will cast the character to an int.